What is x^1/2 =4 ?? HELP??

FluffyCherry

18

x^1/2 =4

And

2x^3/2 = 6x

(edited 8 years ago)

Reply 1

Absent Agent

21

Original post by FluffyCherry

x^1/2= 4

2x^3/2= 6x

For each one you need to treat both sides of the equations such that you make x be on its own, without any coefficients, power ect.

For the first one, you know that if you square both sides you will have x=16.

X^1/2 = root x

OP

Original post by Mehrdad jafari

For each one you need to treat both sides of the equations such that you make x be on its own, without any coefficients, power ect.

For the first one, you know that if you square both sides you will have x=16.

I see, thanx
and how about 2x^3/2 = 6x

Reply 4

Absent Agent

21

Original post by FluffyCherry

I see, thanx
and how about 2x^3/2 = 6x

What do you think first you would have to do with both sides to eliminate the coefficient of x?

(edited 8 years ago)

Reply 5

Zacken

22

Original post by Mehrdad jafari

x

If you want to Latex a superscript with more than one character then enclose it in {}, for example, x^{1/2} produces

x^{1/2}

whilst x^1/2 produces

x^1/2

Reply 6

Zacken

22

Original post by FluffyCherry

I see, thanx
and how about 2x^3/2 = 6x

Factorise and solve.

Reply 7

FluffyCherry

OP

18

Original post by Mehrdad jafari

What do you think first you would have to do with both sides to eliminate the coefficient of x?

2x^3/2 = 6x
2x^3/2 - 6x=0
2x(x^1/2 -3)=0

So 2x =0 Or x^1/2 -3 =0 x^1/2 =3 And now that's the part was I was confused, do I square the
answer or square root it?

(edited 8 years ago)

Reply 8

Kvothe the Arcane

20

Original post by FluffyCherry

2x^3/2 = 6x
2x^3/2 - 6x=0
2x(x^1/2 -3)=0

So 2x =0 Or x^1/2 -3 =0 x^1/2 =3 And now that's the part was I was confused, do I square the
answer or square root it?

Your factorized equation is the same type of problem as part (a)...

Also, it is helpful to realise that

x^{\frac{1}{2}}=\sqrt{x}

.

Reply 9

Absent Agent

21

Original post by Zacken

If you want to Latex a superscript with more than one character then enclose it in {}, for example, x^{1/2} produces

x^{1/2}

whilst x^1/2 produces

x^1/2

Thanks for the advice! i usually don't use latex :smile:

Original post by FluffyCherry

2x^3/2 = 6x
2x^3/2 - 6x=0
2x(x^1/2 -3)=0

So 2x =0 Or x^1/2 -3 =0 x^1/2 =3 And now that's the part was I was confused, do I square the
answer or square root it?