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Physics Question - Please help!

A large oil tanker, of mass 10^8 kg, is travelling in the open ocean at a speed of 10m/s when its engines fail suddenly. The water exerts a retarding force of magnitude Cv on the tanker, where C= 3*10^5 Ns/m and v is the speed of the tanker.
(a) Write down the equation of motion of the tanker
(b) Solve the equation to obtain the speed of the tanker as a function of the time elapsed since the engine failure. Hence find the position of the tanker as a function of time elapsed.
(c) How far will the tanker move before it finally comes to rest?
Original post by Serenaaa
A large oil tanker, of mass 10^8 kg, is travelling in the open ocean at a speed of 10m/s when its engines fail suddenly. The water exerts a retarding force of magnitude Cv on the tanker, where C= 3*10^5 Ns/m and v is the speed of the tanker.
(a) Write down the equation of motion of the tanker
(b) Solve the equation to obtain the speed of the tanker as a function of the time elapsed since the engine failure. Hence find the position of the tanker as a function of time elapsed.
(c) How far will the tanker move before it finally comes to rest?


What level is this? What do you know about solving differential equations? What have you done so far?
Reply 2
Original post by morgan8002
What level is this? What do you know about solving differential equations? What have you done so far?


I have done A level maths, and my teacher gave me this question to 'stretch me,' but I have no idea what to do! I know that you need to use Newton's laws, but that's as much as I know!
Original post by Serenaaa
A large oil tanker, of mass 10^8 kg, is travelling in the open ocean at a speed of 10m/s when its engines fail suddenly. The water exerts a retarding force of magnitude Cv on the tanker, where C= 3*10^5 Ns/m and v is the speed of the tanker.
(a) Write down the equation of motion of the tanker
(b) Solve the equation to obtain the speed of the tanker as a function of the time elapsed since the engine failure. Hence find the position of the tanker as a function of time elapsed.
(c) How far will the tanker move before it finally comes to rest?


So you know the force is given by Cv... I'm assuming you know F = ma? So Cv=-ma (negative since force is opposite direction to velocity of tanker)
remember a=dvdt \vec{a} = \frac{d\vec{v}}{dt} so Cv=mdvdt Cv=-m \frac{dv}{dt} now solve that for v
Reply 4
Original post by langlitz
So you know the force is given by Cv... I'm assuming you know F = ma? So Cv=-ma (negative since force is opposite direction to velocity of tanker)
remember a=dvdt \vec{a} = \frac{d\vec{v}}{dt} so Cv=mdvdt Cv=-m \frac{dv}{dt} now solve that for v


thank you so much! I have finally solved it after HOURS of trying! xx

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