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Formation of Iron(II) iodide? Questions!

So it is Fe(s) + I2(s) ->FeI2(s)

Are group 7 elements in their standard states always I2, Cl2 etc?

Can it not be 2I(s)?

Also why is it a solid, should it not be a solid?

Thanks
Reply 1
Avatar for Pigster
Pigster
20
They're always in their standard states if they're in standard conditions at 298 K. Iodine can exist at separate atoms, i.e. 2I, but they'd have to be as a gas (at a pretty high temp).

It exists as a solid at RTP due to the strength of the VdW forces.
Reply 2
Avatar for Clunkles
Clunkles
9
Original post by Mihael_Keehl
So it is Fe(s) + I2(s) ->FeI2(s)

Are group 7 elements in their standard states always I2, Cl2 etc?

Can it not be 2I(s)?

Also why is it a solid, should it not be a solid?

Thanks


Hi, yes they are always I2 etc. The solid structure looks like lots of I - I "dumbbells" stacked up.
And yeah, iodine is a solid at standard conditions.
Chlorine - gas
Bromine - liquid
Iodine - solid


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