Once again, it's mee
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Original post by Hydeman
Nice one! Did you you round the awkward number you get by square rooting 84.5? It later gives a clean 1 d.p. number when you use trigonometry and the final answer I got was exactly 97.5 cm2 although yours is so close that I don't think any examiner would care.
Edit: Out of interest, what level is this? Is it GCSE, A Level, or one of the Scottish/Irish equivalents of those?
Edit: Out of interest, what level is this? Is it GCSE, A Level, or one of the Scottish/Irish equivalents of those?
This is a Westminster School 13+ exam paper
Original post by User23
This is a Westminster School 13+ exam paper
No worries, I've already been pointed in that direction. xD I was just curious.
Original post by boojiebaba
I know you've already figured it out, but here's my solution anyway
I know you've already figured it out, but here's my solution anyway
Hey, I really like your solution.
But, I don't get how did you do 13/2 = 6.5 and make that one of the sides of the right-angled triangle.
I get how you did 13 cm as the side opposite the right angle is the hypotenuse and then you used pythagoras.
But, you done 13/2 = 6.5?
Can you please explainOriginal post by User23
This is a Westminster School 13+ exam paper
So it's for people over 13? This is like a tough GCSE question!
Original post by Hydeman
No worries, I've already been pointed in that direction. xD I was just curious.
is it possible if u could help me with another question please?
Original post by User23
is it possible if u could help me with another question please?
Post more please
!Original post by User23
is it possible if u could help me with another question please?
Yeah sure.
Original post by User23
thanks so much
So what do you think the first couple of answers are?
I'll tell explain if you get it wrong.s = 1/2 * the sum of all the sides of the triangle
Make this into an equation s = 1/2(.....)
Make this into an equation s = 1/2(.....)
Original post by Hydeman
So what do you think the first couple of answers are? I'll tell explain if you get it wrong.
I'll tell explain if you get it wrong.this is my working out
Original post by User23
this is my working out
The second part where you're rewriting s in terms of a, b and c isn't quite right. You should be getting a formula, not an integer as an answer. I'm not sure why the triangles are there since the question is algebraic but you'd need to play around with the equation (Heron's formula) given. Think about how you can collapse all those s symbols into one (hint: factorise -- but first square both sides).
Original post by Hydeman
The second part where you're rewriting s in terms of a, b and c isn't quite right. You should be getting a formula, not an integer as an answer. I'm not sure why the triangles are there since the question is algebraic but you'd need to play around with the equation (Heron's formula) given. Think about how you can collapse all those s symbols into one (hint: factorise -- but first square both sides).
yeah but i swear it tells u s is half the perimeter of a triangle so i found s to be 12 for the second triangle.:
Original post by User23
yeah but i swear it tells u s is half the perimeter of a triangle so i found s to be 12 for the second triangle.:
It does tell you that but it doesn't ask you to do anything with the triangles just yet. Use the formula they've given and try to rearrange it to make s the subject.
The triangles are for the next question. Your answer should be algebraic, not a number.
Original post by Hydeman
It does tell you that but it doesn't ask you to do anything with the triangles just yet. Use the formula they've given and try to rearrange it to make s the subject. The triangles are for the next question.
Your answer should be algebraic, not a number.
The triangles are for the next question. Your answer should be algebraic, not a number.
oh no ok ill try make s the subject, please don't laugh at my working out if it's wrong
Original post by Hydeman
It does tell you that but it doesn't ask you to do anything with the triangles just yet. Use the formula they've given and try to rearrange it to make s the subject. The triangles are for the next question.
Your answer should be algebraic, not a number.
The triangles are for the next question. Your answer should be algebraic, not a number.
S = (Area)^ / (1-a)(1-b)(1-c)
?
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Original post by User23
oh no ok ill try make s the subject, please don't laugh at my working out if it's wrong
Hmm. I may have misled you on this one. D: I'm thinking it's just s = (a + b + c)/2 as in the first question, even though that makes little sense... For the second equation, you've got that capital A as well which is more or less impossible to get rid of so I'd think it's just the simple answer from part I.
Original post by Chittesh14
No, I'm thinking that's wrong because it includes area, which isn't in the question. I think it's just the simple s = (a + b + c)/2 from earlier although I've no idea why it's repeated. The first question does say calculate but mentions a hypothetical triangle with sides a, b and c so I don't see how you could give a different answer for that...
Is there a markscheme for this anywhere? It shouldn't really be taking this long if it's for 13-year-olds so I'm going to assume that the long way is wrong... (by the way I don't think (s - a) factorises to s(1 -a); it would factorise to s(1 - a/s), which expands back to (s - a)).
Sorry guys.
(edited 8 years ago)
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