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Resistivity AS question HELP

I just have no idea where to start with this question to get a sensible answer...
I've tried rearranging p=RA/L to find L but it doesn't really work :/
I'm probably over complicating it but any help would be much appreciated :smile:20151029_194212-1.jpg
Original post by rainbowtwist
I just have no idea where to start with this question to get a sensible answer...
I've tried rearranging p=RA/L to find L but it doesn't really work :/
I'm probably over complicating it but any help would be much appreciated :smile:20151029_194212-1.jpg


That sounds like a good idea :smile:

What does your calculation look like?
Well, it tells you that your length is 'x'. Therefore, your area must be 'x' to the power of 2 ( as x is multiplied by itself).

So, if you substitute it, the you get p=R(x)2/x

Cancel your x's to get p=Rx

Rearrange and you get x=p/R, which is 5x10-2/5 = 0.01m
Hope this helps :smile:

P.s, if you substitute it into the equation you'll see that the answer for resistivity is 0.05, which is 5x10-2
(edited 8 years ago)
Original post by JC_Costales
Well, it tells you that your length is 'x'. Therefore, your area must be 'x' to the power of 2 ( as x is multiplied by itself).

So, if you substitute it, the you get p=R(x)2/x

Cancel your x's to get p=Rx

Rearrange and you get x=p/R, which is 5x10-2/5 = 0.01m
Hope this helps :smile:

P.s, if you substitute it into the equation you'll see that the answer for resistivity is 0.05, which is 5x10-2


Thank you !! Yes I understand - I had the right idea but I think I was getting myself all confused because I rearranged it first and subbed in R straight away :rolleyes:
Original post by rainbowtwist
Thank you !! Yes I understand - I had the right idea but I think I was getting myself all confused because I rearranged it first and subbed in R straight away :rolleyes:


It's Ok!!!! everyone makes little slip ups once in a while, it's what makes us fundamentally human :biggrin:

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