The Student Room Group

maths c1 differentiation

8x-1 ... how do i differentiate with respect to x?
write as 8x1 -1x0

then apply the rules for differentiating axn
Original post by caitlindavies
8x-1 ... how do i differentiate with respect to x?


Differentiate each term with respect to x.

How do you differentiate the general term ax^n, where a and n are numbers, with respect to x?
Original post by caitlindavies
8x-1 ... how do i differentiate with respect to x?

Times by the power and then take one away from the power.
For example 16x^2 would be 32x. You're timesing by the power (2) and then taking one away from the power (2-1).

Hope that makes it clearer as to how to do your question.

Sent from my LG-D855 using Tapatalk
Original post by caitlindavies
8x-1 ... how do i differentiate with respect to x?


Is that 8/x ?

Use the rule for ax^n ... d/dx =
Reply 5
d/dx[axn] = naxn-1
Original post by ultimatesword
Times by the power and then take one away from the power.
For example 16x^2 would be 32x. You're timesing by the power (2) and then taking one away from the power (2-1).

Hope that makes it clearer as to how to do your question.

Sent from my LG-D855 using Tapatalk


but there is no power?
Reply 7
Original post by caitlindavies
but there is no power?


There is, it's just 1 and 0.

1 is 1x^0. remember that power of 0 makes 1.
(edited 8 years ago)
for example, y = 10x + 2
if you differentiate y with respect to x, you'd get dy/dx = 10
so does the answer to 8x-1 dy/dx + 8?
Original post by caitlindavies
so does the answer to 8x-1 dy/dx + 8?


if you meant '=' when you said '+' you are correct.
yeah i did woah thank you that makes sense now!!
Original post by caitlindavies
but there is no power?


everything has a power, but people don't usually write the power if the value is to the power of 1.

Quick Reply

Latest