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Probability rule question,help

is P(A∩B') the same as P'(B∩A)
Original post by youreanutter
is P(A∩B') the same as P'(B∩A)


No, " P' " has no meaning.

If you meant another combination of A and B, then you may find a Venn diagram useful.
Original post by ghostwalker
No, " P' " has no meaning.

If you meant another combination of A and B, then you may find a Venn diagram useful.


??
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Avatar for skalra
skalra
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Original post by youreanutter
is P(A∩B':wink: the same as P'(B∩A)


P(A∩B') means those elements which are in A and not B.

Consider the experiment of rolling a die.
Let A be the event 'getting a prime number' , B be the event ' getting an odd number' . So,
A= {2,3,5}
B= {1,3,5}

So, A∩B' will be {2}
and P (A∩B') will be equal to 1/6.

(A∩B) = {3,5}
(A∩B)' = {1,2,4,6}
So, P(A∩B)' = 4/6

So, these 2 are not same.

Let me know if there is any confusion now.
Original post by skalra
P(A∩B':wink: means those elements which are in A and not B.

Consider the experiment of rolling a die.
Let A be the event 'getting a prime number' , B be the event ' getting an odd number' . So,
A= {2,3,5}
B= {1,3,5}

So, A∩B' will be {2}
and P (A∩B':wink: will be equal to 1/6.

(A∩B) = {3,5}
(A∩B)' = {1,2,4,6}
So, P(A∩B)' = 4/6

So, these 2 are not same.

Let me know if there is any confusion now.


thanks that helped a lot

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