Maths non calc paper

hi everyone! i would be very grateful if anyone doing gcse maths could post topics that ALWAYS come up on the non calculator paper, as i have my mock exam tomorrow.
Thank you!

· Simultaneous Equations · Expand · Factorise · Quadratics · Substitute· Including Tables and TreeDiagrams· Straight line y=mx+c · Quadratics· Inverse etc· Draw· Tabulate· Link equations to graphs· Rotation· Reflections· Translation· Enlargement

hi everyone! i would be very grateful if anyone doing gcse maths could post topics that ALWAYS come up on the non calculator paper, as i have my mock exam tomorrow.
Thank you!

Adding.

Mine is in two days, how exciting.

Mines tomorrow. I know the feeling!

Mines tomorrow. I know the feeling!

mine is tomorrow
confident i will get an A* in maths
already did but my next challenge is to get full marks or get over 90+ on each paper

Is there anything you find difficult in particular? Perhaps I could help.

Get you, what do you think is the hardest question that comes up in the paper?

mine is tomorrow
confident i will get an A* in maths
already did but my next challenge is to get full marks or get over 90+ on each paper

I wish that could be me! Hopeful to get an A* but it's the one that I'm least confidant on.

dw m8
i know u will get it

Vectors is the death of me. Help would be much appreciated.

Well let's see, vectors are the way we represent the distance something covers and in what direction it moves. They are written in the form (x,y), showing how far it travels based on the value of each axis, and whether they are moving in a negative (-x,-y) or positive (x,y) direction.

Here is a possible exam question:

Triangle A moves by vector [4,-2] to form triangle B.
Draw the position of Triangle B.

How to answer the question:
-choose any of the three points of triangle A, for example the point creating the right angle(facing the hypotenuse), is [6,3].
-move the amount specified in the vector, first by the x axis, then by the y axis.
-so from [6,3], we move four to the right [positive direction of the x axis is the right] , and two down [negative direction of the y axis is down].
-If done correctly, you will find the point used will be at co-ordinates [10,1].
-Draw the triangle based on the lengths in triangle A.

I'm confused on f(x) graphs

As in transformations of grahps?

If you are told f(x) = x^2+2x+2, and y=f(x), this is saying that y is a function of x... the input is x, and the output is f(x) or y.

For transformations you will probably just be shown a graph and given a few points on the graph and asked to sketch the new graph or give the positions of new points.

You have to remember the different transformations of the graph y=f(x):

-> y=-f(x) - reflection in the x axis - all y coordinates change signs
-> y=f(-x) - reflection in the y axis - all x coordinates change signs
-> y= f(x+a) - translation by vector (-a,0) - subtract a from all x coordinates - moves right if a>0 and left if a<0
-> y=f(x)+a - translation by vector (0,a) - add a to all y coordinates
-> y=f(ax) - stretch in the x axis - divide all x coordinates by a
-> y=af(x) - stretch in the y axis - multiply all y coordinates by a

I try and remember these by thinking that for the translation/stretch where something is added inside the bracket, i.e in f(x+a), the a is inside the bracket, you do the opposite to what you would expect on first glance - so subtract a rather than add a. Also all changes where the transformation is in the bracket affects x coordinates and all changes where the transformation is outside the bracket affects y coordinates.