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S3 - Cumulative Distribution Function - Related Variables

The Length, X, of a square has a uniform distribution over the interval from 1 to 6. Find the probabillity density function of Y, the area of the square.

I have made a simple error somewhere but really cannot spot it. My p.d.f should be 1/10(y^(-1/2)) but I am getting 1/5(y^(-1/2)) in the interval between 1 and 36 ...image.jpg
Oh..is it because X is 1 to 1 over the required interval??
Original post by Mathematicus65
The Length, X, of a square has a uniform distribution over the interval from 1 to 6. Find the probabillity density function of Y, the area of the square.

I have made a simple error somewhere but really cannot spot it. My p.d.f should be 1/10(y^(-1/2)) but I am getting 1/5(y^(-1/2)) in the interval between 1 and 36 ...image.jpg


I haven't read all the way through, but notice that you know that the random variable X is positive valued. Therefore when you come to calculate P(X2<y)P(X^2 < y), you only need to consider the positive square root.

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