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Not sure why this is done this way (Pie Chart question)

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Original post by ByronicHero
I was never in year 11.


take your poetic crap somewhere else Shakespeare :smug:
Original post by Mayhem™
take your poetic crap somewhere else Shakespeare :smug:


I mean it literally.
Original post by ByronicHero
I mean it literally.


elaborate :K:
Original post by Mayhem™
elaborate :K:


Edit: Why will nobody help me do a maths.
(edited 8 years ago)
Je mange le foot
Wait this isn't the french thread...
*flies away*
Original post by homeland.lsw
Je mange le foot
Wait this isn't the french thread...
*flies away*


say this to your teacher;

"voulez vous coucher avec moi ce soir ?"
Original post by Mayhem™
say this to your teacher;

"voulez vous coucher avec moi ce soir ?"


PRSOM :biggrin:
Original post by Mayhem™
say this to your teacher;

"voulez vous coucher avec moi ce soir ?"


ma prof de francais est une femme obèse donc je ne pense pas que je le dirais
Original post by TeeEm
Usually it would have been my pleasure
@Zacken @physicsmaths @16Characters....
please take over as I have been stuck on this PDE for the last 3 hours and I need to finish tonight


Nobody helped me :frown:

In an acute-angled triangle ABC the interior bisector of the angle A intersects BC at L and intersects the circumcircle of ABC again at N. From point L perpendiculars are drawn to AB and AC, the feet of these perpendiculars being K and M respectively. Could you please help me prove that the quadrilateral AKNM and the triangle ABC have equal areas?
Reply 29
Original post by ByronicHero
Nobody helped me :frown:

In an acute-angled triangle ABC the interior bisector of the angle A intersects BC at L and intersects the circumcircle of ABC again at N. From point L perpendiculars are drawn to AB and AC, the feet of these perpendiculars being K and M respectively. Could you please help me prove that the quadrilateral AKNM and the triangle ABC have equal areas?


what have you done so far?

@Renzhi10122
(edited 8 years ago)
Original post by ByronicHero
Nobody helped me :frown:

In an acute-angled triangle ABC the interior bisector of the angle A intersects BC at L and intersects the circumcircle of ABC again at N. From point L perpendiculars are drawn to AB and AC, the feet of these perpendiculars being K and M respectively. Could you please help me prove that the quadrilateral AKNM and the triangle ABC have equal areas?


I dnt even have internet so I cnt help. But note the arcs are of same legth and use simlar triangles. This a BMO1 question right?
Original post by ByronicHero
Nobody helped me :frown:

In an acute-angled triangle ABC the interior bisector of the angle A intersects BC at L and intersects the circumcircle of ABC again at N. From point L perpendiculars are drawn to AB and AC, the feet of these perpendiculars being K and M respectively. Could you please help me prove that the quadrilateral AKNM and the triangle ABC have equal areas?


Notice that this reduces down to proving that [KLB]+[MLC]=[KLN]+[MLN]. Now notice that the two pairs of triangles share a side, and KL=ML, and so you want to prove that KB+LC=the two perpendicular distances from N to KL and N to ML.
(edited 8 years ago)

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