hard gcse question

Amy is one third the age of her mother. in 12yrs time amy will be half the age of her mother. how old is amy and her mother? @Zacken

What have you tried? Let's call the age of her mother m (current age) and Amy's age a (current age) Then you know that (now) $a = \frac{m}{3}$

And you also know that (in twelve years time) $a + 12 = \frac{m+12}{2}$, can you solve this simultaneous equation?

Moving this to maths.

i don't get it.. can you explain it in detail

...

So if Amy's age is a and her mothers age is m, then we know that a is m divided by 3 because Amy's age (a) is a third of her moths age. So $a = \frac{m}{3}$, do you understand this?



Full solutions are against forum guidelines.

and two positive numbers x and y, where x is the larger of the two numbers, have a difference of one and a product of 72. using algebra and showing your working find the values of x and y @Zacken

Well, if their difference is $1$ then we know that $x-y=1$. If their product is 72, then we can write: $xy =72$.

Now, remember that $x-y=1$, which is the same thing as $x = y+1$, so: $xy = 72$ can be written as $y(y+1)=72$, now can you solve this?

Here is a lovely gcse question my friend sent me a few years ago, and i've never forgot it (and always kept it saved)



Edit: for you to try after of course , so off topic but its too good not to share

Solution

So if Amy's age is a and her mothers age is m, then we know that a is m divided by 3 because Amy's age (a) is a third of her moths age. So $a = \frac{m}{3}$, do you understand this?



Full solutions are against forum guidelines.

ahaha, of course you reply with the solution to a gcse question

why have you guys 'hijacked' my thread? do unto others as you want others to do unto you!

can you post the full solution in my inbox then cuz i don't get it still?

no we havent, its 3 posts... plus youre getting help from others, plus that question i posted is for you to try, plus if i posted an alevel question and someone posted me another one to try afterwards id be pretty pleased tbh...



...plus this the worst thing you could request

you are genius

yes you have. it is 'irrelevant trash' to my question.. remember this yesterday? and this is not a ****ing homework.. i am just solving questions so what do you mean it is the worst thing i could request?

"irrelevant trash"... i do not remember as it was probably zacken who said that yesterday

I am 90% sure you wont learn from the full solution just from your previous posts, thats all

also dont get angry please, if you think i have "hijacked" your thread by giving you another question to solve then I wont do it again

What have you tried? Let's call the age of her mother m (current age) and Amy's age a (current age) Then you know that (now) $a = \frac{m}{3}$

And you also know that (in twelve years time) $a + 12 = \frac{m+12}{2}$, can you solve this simultaneous equation?

Moving this to maths.