Chemistry help

Thanks but I'm confused now aha - is 84 not the RFM?

Otherway round, it's 16.8/84, don't worry about it everyone finds some stuff difficult. so now you know how many moles of nahco3 there are, you know by ratio that there are half the number of moles of na2co3. Then you just need to convert that back into a mass you can use

45
Na X 2 =46
C=12
o=32
90/2= 45
As we have half

3 oxygens, meaning the total mass of one mole would be 46+12+48 = 106. We had 16.8/84 moles of sodium hydrogen carbonate = 0.2 moles, so how many moles do we expect to produce of na2co3

9.20/106 = 0.08679..:::../

We had 0.2 moles of nahco3, and from the ratio we know that for every 2 moles of nahco3 there is one mole of na2co3. Therefore the max yield would be 0.1 moles of naco3, so we then need to multiply the RFM (106) bu=y 0.1 in order to find the max yield in grams

1,060

Oops, meant to quote the other person who said that the RFM of 2 moles was 168, which doesn't really make sense since the definition of RFM is that it's the mass of one mole of the compound relative to 12g of carbon 12. Ignore me lol

10.6 yes, so then the % yield will just be the yield we actually got (9.2) divided by 10.6 times 100

Ah that makes sense so that's 86.79%

So can I clarify the steps for this So I can practice.

Look at product we start with and products we produce
We see there's a H2O and that's only possible if we started with 2NaHCO3 for there to be two hydrogen as a product.

We look at what we collect which is Na2CO3 sodium carbonate
We work out the relative mass of 2NaHCO3 sodium hydrogenated and then divide what we had to start by the maximum amount we could have made 16.8/84 0.2moles
Then do the same for the sodium carbonate NaHCO3 has a Ar of 106 we divide
9.20/106 = 0.08679 * 100 86.79% of sodium carbonate we actually made

Is that right

Almost. Actually the easiest way to know there's 2 nahco3 is that na2co3 has 2 sodiums so there has to be 2 nahco3. Your method for the first bit is correct up unti lthe moles up until 0.2. That 0.2 is not the number of moles we could create, it's how many moles of NaHco3 we had at the start. You then need to look at the mole ratios to work out how many moles of the product that would give, so in this case 0.2 moles of NaHCO3 reacting would give 0.1 moles of Na2co3. You would then multiply the maximum possible number of moles of the product (in this case 0.1) by the mass of the product, so 0.1 x 106 = 10.6g max yield. You then divide 9.2/10.6 and x100

Is that because sodium is diatomic?! how do we know this (so in this case 0.2 moles of NaHCO3 reacting would give 0.1 moles of Na2co3) I'm sorry I just want to make sure I completely understand so you don't have to explain it to me again tomorrow... I think in understanding it I just need to clarify the method and how go through the process.... Thank you for your help

Go back to the original balanced equation, that tell us for every 1 mole of na2co3 there is there are 2 moles of nahco3. Or to put it another way, 2moles of nahco3 react to form one mole of na2co3, so if we have a 10th of that amount (0.2 moles) 0.2 moles must react to form 0.1 moles

But we balanced the equation by realising that H must be in the original compound twice... I don't understand fully how that tells us for 1 mile of na2co3 we have 2 miles of nahco3.... Sorry

Almost. Actually the easiest way to know there's 2 nahco3 is that na2co3 has 2 sodiums so there has to be 2 nahco3. Your method for the first bit is correct up unti lthe moles up until 0.2. That 0.2 is not the number of moles we could create, it's how many moles of NaHco3 we had at the start. You then need to look at the mole ratios to work out how many moles of the product that would give, so in this case 0.2 moles of NaHCO3 reacting would give 0.1 moles of Na2co3. You would then multiply the maximum possible number of moles of the product (in this case 0.1) by the mass of the product, so 0.1 x 106 = 10.6g max yield. You then divide 9.2/10.6 and x100

doesn't matter why we balanced the equation the important bit is that the equation is 2 NaHco3 -> 1 Na2co3 ...

Yeah but I don't know how I figure I have a 2:1 ratio that's the only bit I don't understand

because in order to balance the equation you had to have 2 nahco3