Hi! I have a chemistry question that I'm not sure about. Answers and how to do it would be appreciated!
0.1g of an unknown group 2 metal (which we shall call M) was dropped into distilled water in a conical flask. Some effervescence, and a small amount of white precipitate, was observed. The resulting mixture required 22.8cm3 of 0.1 moldm-3 hydrochloric acid to neutralise. Calculate the Ar of the metal, and deduce its identity. a. Equation for reaction of M with water: I guessed it would be: M + H2O ------> MO + H2 b. Equation for reaction of resulting mixture with HCl: I again guessed it would be this: MO + 2HCl ------> MCl2 + H2 c. Ar and identity of metal. I have no idea how to get this answer.
By the looks of it, ork out the mols of HCL and using your equation, you know the molar ratio and can work out the mols of the metal. Then rearrange mols = Mass/mr to work out ar.
Hi! I have a chemistry question that I'm not sure about. Answers and how to do it would be appreciated!
0.1g of an unknown group 2 metal (which we shall call M) was dropped into distilled water in a conical flask. Some effervescence, and a small amount of white precipitate, was observed. The resulting mixture required 22.8cm3 of 0.1 moldm-3 hydrochloric acid to neutralise. Calculate the Ar of the metal, and deduce its identity. a. Equation for reaction of M with water: I guessed it would be: M + H2O ------> MO + H2 b. Equation for reaction of resulting mixture with HCl: I again guessed it would be this: MO + 2HCl ------> MCl2 + H2 c. Ar and identity of metal. I have no idea how to get this answer.
Thanks in advance
Your equations are incorrect. Do you remember what is formed when a group 2 metal is added to water? (Only one product)
By the looks of it, ork out the mols of HCL and using your equation, you know the molar ratio and can work out the mols of the metal. Then rearrange mols = Mass/mr to work out ar.