[br][br]\displaystyle \frac{A-x}{A+x} = \frac{A-y}{A+y} \frac{A-z}{A+z}[br][br][br]\[\textrm{The answer is:}\][br] [br]x = \displaystyle \frac{y+z}{1+ (\frac{yz}{A^2})}[br][br]
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\displaysyle \frac{A-x}{A+x} = k \Rightarrow A - x = k(A+x) \Rightarrow A - x = kA + kx
\displaysyle \frac{A-x}{A+x} = k \Rightarrow A - x = k(A+x) \Rightarrow A - x = kA + kx
\displaysyle \frac{A-x}{A+x} = k \Rightarrow A - x = k(A+x) \Rightarrow A - x = kA + kx
\displaysyle \frac{A-x}{A+x} = k \Rightarrow A - x = k(A+x) \Rightarrow A - x = kA + kx
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