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Enthalpy change for the neutralisation

image.jpgCan somebody please help me I haven't a clue what this is talking about
Original post by robzpotter
image.jpgCan somebody please help me I haven't a clue what this is talking about


Your formulae for both nitric acid and potassium hydroxide are incorrect.

Energy released = mass (of solution) x specific heat capacity (4.18) x temperature change

To get energy per mol you must divide by the number of moles reacting.

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