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the 200N/m @ the R2 end is doing my head in.

Could someone slowly walk me through it .

Cheers
2 Calculate the reactions R1 and R2 on the loaded beam shown below (2).docx40.6KB
Original post by Keats1982
the 200N/m @ the R2 end is doing my head in.

Could someone slowly walk me through it .

Cheers
Because it's an equally distributed load, calculate the total force (exerted by that load) to act at the centre of the distribution and then work the problem as for discrete point loads.

i.e.

200Nm−1 x 3.75m=750N200\rm{Nm^{-1}}\ x\ 3.75m = 750N

acting at

8−(3.752)=6.125m\rm{8 - (\frac{3.75}{2})} = 6.125m from R1
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Keats1982
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Blown my mind lol.

Thanks for the response.

I will have another stressful night trying to work it out .

GRRRRRRR

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