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Maths. Please Help

A circle passes through the points (2,0) and (8,0) and has the y axis as a tangent. What is the 2 equations for the cirlce.
(edited 8 years ago)
Is there no simultaneous equation with it? Usually you'd put the two intercepts into the simultaneous equation and the solutions for them both would be your two solutions
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Zacken
22
Original post by L_Azazel
A circle passes through the points (2,0) and (8,0) and has the y axis as a tangent. What is the 2 equations for the cirlce.


Do you recall the fact that the equation of a circle is (x-a)^2 + (y-b)^2 = r^2?

What does the circle being tangent to the y-axis imply? Try drawing a sketch.
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Zacken
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Moved to maths.
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L_Azazel
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Original post by Zacken
Moved to maths.


Yes I recall, but I don't know the centre?
Original post by Zacken
Do you recall the fact that the equation of a circle is (x-a)^2 + (y-b)^2 = r^2?

What does the circle being tangent to the y-axis imply? Try drawing a sketch.


Original post by L_Azazel
Yes I recall, but I don't know the centre?


(x-a)^2 + (y-b)^2 = r^2 <---- the x and y in those are the centre of the circle co-ordinates
Reply 6
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Zacken
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Original post by thefatone
(x-a)^2 + (y-b)^2 = r^2 <---- the x and y in those are the centre of the circle co-ordinates


No they're not, that's a and b. :-)
Original post by Zacken
No they're not, that's a and b. :-)


oh yea xD

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