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you need to solve dy/dx = 0 to find the minimum point.

used the x value provided once you have the gradient function... that will give you a.

then go back to y = .....

to find b.
y=x^2+ax+b
Min pt(-2,5)
so y=(x+2)^2+5
extand this equtation to get in y=x^2+ax+b form
Original post by the bear
you need to solve dy/dx = 0 to find the minimum point.

used the x value provided once you have the gradient function... that will give you a.

then go back to y = .....

to find b.


This isn't in Edexcel C1, it's in C2.
Original post by cherrycaptain
y=x^2+ax+b
Min pt(-2,5)
so y=(x+2)^2+5
extand this equtation to get in y=x^2+ax+b form


Ok thanks I think I get that

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