\displaystyle[br] \begin{equation*}9x^3 + 21x^2 + 6x = x(9x^2 +21x+ 6) = 3x(x+2)(3x+1)\end{equation*}
\displaystyle[br]\begin{equation*} \frac{9x^3 + 21x^2 + 6x}{f(x)} = \frac{3x(x+2)(3x+1)}{(x+2)(3x-1)(3x+1)}\end{equation*}
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