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Soloman C4 Paper A. Question 8

I calculated the gradient of the tangent at P to be (-(6)^(1/2))/6
Therefore i thought that the gradient of the normal would be (6)/((6)^(1/2)).
Can you please explain how this is wrong.
https://5c59854d0ccd29d489c9e5e689a8bbadf49aa0f0.googledrive.com/host/0B1ZiqBksUHNYREhxMHhfam1IQm8/for-OCR/Solomon%20A%20QP%20-%20C4%20OCR.pdf

Thanks.
Reply 1
Avatar for joostan
joostan
13
Original post by SamuelN98
I calculated the gradient of the tangent at P to be (-(6)^(1/2))/6
Therefore i thought that the gradient of the normal would be (6)/((6)^(1/2)).
Can you please explain how this is wrong.
https://5c59854d0ccd29d489c9e5e689a8bbadf49aa0f0.googledrive.com/host/0B1ZiqBksUHNYREhxMHhfam1IQm8/for-OCR/Solomon%20A%20QP%20-%20C4%20OCR.pdf

Thanks.


What makes you think it's wrong?
Original post by SamuelN98
I calculated the gradient of the tangent at P to be (-(6)^(1/2))/6
Therefore i thought that the gradient of the normal would be (6)/((6)^(1/2)).
Can you please explain how this is wrong.
https://5c59854d0ccd29d489c9e5e689a8bbadf49aa0f0.googledrive.com/host/0B1ZiqBksUHNYREhxMHhfam1IQm8/for-OCR/Solomon%20A%20QP%20-%20C4%20OCR.pdf

Thanks.


It is correct..

Maybe you just need to think about what 6/root6 is :tongue:
Reply 3
Avatar for Zacken
Zacken
22
Original post by SamuelN98
I calculated the gradient of the tangent at P to be (-(6)^(1/2))/6
Therefore i thought that the gradient of the normal would be (6)/((6)^(1/2)).
Can you please explain how this is wrong.
https://5c59854d0ccd29d489c9e5e689a8bbadf49aa0f0.googledrive.com/host/0B1ZiqBksUHNYREhxMHhfam1IQm8/for-OCR/Solomon%20A%20QP%20-%20C4%20OCR.pdf

Thanks.


It might help if you realise that 66=6161/2=61−1/2=61/2=6\frac{6}{\sqrt{6}} = \frac{6^1}{6^{1/2}} = 6^{1-1/2} = 6^{1/2} = \sqrt{6}
Reply 4
Avatar for Zacken
Zacken
22
Yep, nevermind...
Reply 5
Avatar for SamuelN98
SamuelN98
OP
5
Thanks for the quick responses!
I didn't think of it like that, if there equivalent is it suitable in an answer to continue using 6/((6)^(1/2)).
Reply 6
Avatar for joostan
joostan
13
Original post by SamuelN98
Thanks for the quick responses!
I didn't think of it like that, if there equivalent is it suitable in an answer to continue using 6/((6)^(1/2)).


I don't see why not, as a simplified answer is not necessary for this show that question, that said, why would you bother?
Original post by SamuelN98
Thanks for the quick responses!
I didn't think of it like that, if there equivalent is it suitable in an answer to continue using 6/((6)^(1/2)).


I suppose so, but it's more difficult to do or see things than if you just simplify it straight away.
Reply 8
Avatar for SamuelN98
SamuelN98
OP
5
I`m not sure id see the relationship straight away. Should do now though.
Reply 9
Avatar for Zacken
Zacken
22
Original post by SamuelN98
I`m not sure id see the relationship straight away. Should do now though.


That's how it was for all of us, it'll become amazingly transparent after some practice! :smile:

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