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practising latex

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Original post by thefatone
x=19(2106297437833+22/397437833) x = \dfrac{1}{9}\left(-2-106 \sqrt[3]{ \dfrac{2}{9\sqrt{7437} -83} }+ 2^{2/3} \sqrt[3]{ 9\sqrt {7437} -83 }\right)


i have failed help


..
(edited 8 years ago)
Reply 41
Original post by thefatone
Unparseable latex formula:

x = \dfrac{1}{9} \left( -2 -106 \sqrt[3] \dfrac{2}{9\times \sqrt{7437} -83} + 2^{2/3} \times \sqrt[3] 9 \times \sqrt {7437} -83 \right)




i have failed help


I don't know how to use LaTeX I just use the TSR guide if I ever need to
Reply 42
Original post by EricPiphany
..



wtf happened there? mine looked like

Original post by 1 8 13 20 42
I don't know how to use LaTeX I just use the TSR guide if I ever need to


what this guy quoted ^^
Original post by thefatone
wtf happened there? mine looked like



what this guy quoted ^^


Click on it and check. I edited it a little. Braces.
Original post by thefatone
wtf happened there? mine looked like



He edited so you'd know what you did wrong.

His x=19(2106297437833+22/397437833)x = \dfrac{1}{9}\left(-2-106 \sqrt[3]{ \dfrac{2}{9\sqrt{7437} -83} }+ 2^{2/3} \sqrt[3]{ 9\sqrt {7437} -83 }\right)
x = \dfrac{1}{9}\left(-2-106 \sqrt[3]{ \dfrac{2}{9\sqrt{7437} -83} }+ 2^{2/3} \sqrt[3]{ 9\sqrt {7437} -83 }\right)
Yours
Unparseable latex formula:

x = \dfrac{1}{9} \left(-2-106 \sqrt[3] \dfrac{2}{9\times \sqrt{7437} -83} + 2^{2/3} \times \sqrt[3] 9 \times \sqrt {7437} -83 \right)


x = \dfrac{1}{9} \left( -2 -106 \sqrt[3] \dfrac{2}{9\times \sqrt{7437} -83} + 2^{2/3} \times \sqrt[3] 9 \times \sqrt {7437} -83 \right)
(edited 8 years ago)
Reply 45
Original post by 1 8 13 20 42
I don't know how to use LaTeX I just use the TSR guide if I ever need to


Original post by EricPiphany
Click on it and check. I edited it a little. Braces.


Unparseable or potentially dangerous latex formula. Error 4: no dvi output from LaTeX. It is likely that your formula contains syntax errors or worse.x = \dfrac{1}{9} \left( -2 -106 \sqrt[3] {\dfrac{2}{9\times \sqrt{7437} -83} + 2^{2/3} \times \sqrt[3] 9 \times \sqrt {7437} -83 \right)

i've broken it
Reply 46
Original post by Kvothe the arcane
He edited so you'd know what you did wrong.

His x=19(2106297437833+22/397437833)x = \dfrac{1}{9}\left(-2-106 \sqrt[3]{ \dfrac{2}{9\sqrt{7437} -83} }+ 2^{2/3} \sqrt[3]{ 9\sqrt {7437} -83 }\right)
x = \dfrac{1}{9}\left(-2-106 \sqrt[3]{ \dfrac{2}{9\sqrt{7437} -83} }+ 2^{2/3} \sqrt[3]{ 9\sqrt {7437} -83 }\right)
Yours
Unparseable latex formula:

x = \dfrac{1}{9} \left(-2-106 \sqrt[3] \dfrac{2}{9\times \sqrt{7437} -83} + 2^{2/3} \times \sqrt[3] 9 \times \sqrt {7437} -83 \right)


x = \dfrac{1}{9} \left( -2 -106 \sqrt[3] \dfrac{2}{9\times \sqrt{7437} -83} + 2^{2/3} \times \sqrt[3] 9 \times \sqrt {7437} -83 \right)


oh ok thanks my derpy number looks quite cool though
Original post by thefatone
oh ok thanks my derpy number looks quite cool though

If you want more practice lol
Capture.PNG
Reply 48
Original post by EricPiphany
If you want more practice lol
Capture.PNG


let's do this sh*t
Original post by thefatone
let's do this sh*t


you can simplify it a bit if you want. algebraically.
Reply 50
Original post by EricPiphany
If you want more practice lol
Capture.PNG


Unparseable latex formula:

\dfrac{g}{\omega ^2}\left( {\sqrt \left( \dfrac {\omega ^2 x}{g}\right)^2 +1} - in\left( \dfrac {\sqrt \left(\dfrac {\omega^2 x}{g} \right)^2 +1}{\dfrac{\omega^2 x}{g}}\right)\right)+C



we ****ed this one up too ;( :colonhash:
(edited 8 years ago)
Original post by thefatone
3x3+2x2+24x+8=03x^3+2x^2+24x+8=0

it worked :biggrin:

trying fractions

x+329x2\dfrac{x+3}{29-x^2}



(34)\dbinom{3}{4}


Q=mcΔt Q=mc\Delta t

0210x+5x2x dx=37850x29050!\displaystyle\int^2_0\sqrt[x]{10x+5x^2}\ dx = \dfrac{378-50x^{290}}{50!}


Not sure if anyone's mentioned this yet but the best way of practising LaTeX in my opinion is downloading a program like TexMaker and doing your maths problems on it. Takes ages at the start but you'll soon get to the point where you can input data extremely rapidly. And your homework will look so impressive!

Takes a bit more work than Latex on TSR because of some other little code snippets you've got to worry about but you can use it to export pdf documents so it's genuinely useful.
(edited 8 years ago)
Reply 54
Original post by Plagioclase
Not sure if anyone's mentioned this yet but the best way of practising LaTeX in my opinion is downloading a program like TexMaker and doing your maths problems on it. Takes ages at the start but you'll soon get to the point where you can input data extremely rapidly. And your homework will look so impressive!

Takes a bit more work than Latex on TSR because of some other little code snippets you've got to worry about but you can use it to export pdf documents so it's genuinely useful.

just a little thing to do to help me when i come and ask for maths help then i can use the proper signs as such


thanks

\displaystyle \frac{g}{\omega^2} \left( \sqrt{ \left( \frac{\omega^2 x}{g} \right)^2+1} - \ln \left( \frac{ \sqrt{ \left( \frac{\omega^2 x}{g} \right)^2+1} }{ \frac{\omega^2 x}{g} } \right) \right) + C

\dfrac{g}{\omega ^2}\left( \sqrt \left( \dfrac {\omega ^2 x}{g}\right)^2 +1 - in\left(\dfrac {\sqrt \left( {\omega ^2 x}{g}\right)^2 +1}{\dfrac \omega ^2 x}{g}}\right)right) +C
Original post by thefatone
just a little thing to do to help me when i come and ask for maths help then i can use the proper signs as such


I know, just saying that being able to use a LaTeX compiler is a genuinely useful skill that doesn't require a lot of effort on top of what you already know which could help you impress in the future :smile:
Reply 56
Original post by thefatone
Unparseable latex formula:

\dfrac{g}{\omega ^2}\left( {\sqrt \left( \dfrac {\omega ^2 x}{g}\right)^2 +1} - in\left( \dfrac {\sqrt \left(\dfrac {\omega^2 x}{g} \right)^2 +1}{\dfrac{\omega^2 x}{g}}\right)\right)+C



we f**ked this one up too ;( :colonhash:




done it :biggrin:
Original post by thefatone
done it :biggrin:


next project
Capture.PNG
Reply 58
Original post by EricPiphany
next project
Capture.PNG


dT(x)dx=ρg(dydx+dxdy)\dfrac{\mathrm{d}T \left(x\right)}{\mathrm{d}x} = -\rho g \left( \dfrac {\mathrm{d}y}{\mathrm{d}x} + \dfrac {\mathrm{d}x}{\mathrm{d}y}\right)

yay first time
Reply 59
Original post by thefatone
dT(x)dx=ρg(dydx+dxdy)\dfrac{\mathrm{d}T \left(x\right)}{\mathrm{d}x} = -\rho g \left( \dfrac {\mathrm{d}y}{\mathrm{d}x} + \dfrac {\mathrm{d}x}{\mathrm{d}y}\right)

yay first time


And better then the picture (loving the d\mathrm{d}'s) - well done!

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