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Trigonometry help please

Hey guys,

Could someone please show me how to do the following questions. I would be very grateful.
Thanks in advance to anyone who helps :smile:

For part A) do I divide 1 by 3 first then square root or square root first then divide by 3?

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For questions like these, your aim first is to isolate the trign(x) function so you can then take the nth root of both sides. So what you thought of doing first is correct
For part A) Divide 1 by 3 first then square root (I think)
Original post by Aty100
Hey guys,

Could someone please show me how to do the following questions. I would be very grateful.
Thanks in advance to anyone who helps :smile:

For part A) do I divide 1 by 3 first then square root or square root first then divide by 3?


remember that

3tan2θ=13\tan ^2 \theta = 1

is the same as

3(tanθ)2=1 3\left( \tan \theta \right)^2 = 1

yay it came out right :u:
(edited 8 years ago)
It doesn't matter if you divide 1 by 3 first or do the square root first (and then divide by root 3, not 3). Bear in mind there may be two possible real solutions for a quadratic if the discriminant is >0.

Both those equations involve special angles, which you should memorise. In this case the special angles are sin(pi/4) = 1/(root2), sin(pi/6) = 1/2 and cos(pi/6) = (root3)/2.
Original post by Student403
For questions like these, your aim first is to isolate the trign(x) function so you can then take the nth root of both sides. So what you thought of doing first is correct


wait a sec, but root 1 is 1????
Original post by thefatone
remember that

3tan2θ=13\tan ^2 \theta = 1

is the same as

(3tanθ)2=1 \left( 3 \tan \theta \right)^2 = 1

yay it came out right :u:

Came out right but it's wrong :wink:.
Original post by thefatone
wait a sec, but root 1 is 1????


Huh?
Original post by thefatone
remember that

3tan2θ=13\tan ^2 \theta = 1

is the same as

(3tanθ)2=1 \left( 3 \tan \theta \right)^2 = 1

yay it came out right :u:

Nooo
Original post by Unkempt_One
Came out right but it's wrong :wink:.


remember that

3tan2θ=13\tan ^2 \theta = 1

is the same as???

3(tanθ)2=1 3\left( \tan \theta \right)^2 = 1 ?????
Original post by thefatone
remember that

3tan2θ=13\tan ^2 \theta = 1

is the same as???

3(tanθ)2=1 3\left( \tan \theta \right)^2 = 1 ?????


Yup
Original post by Student403
Nooo


was it you?

i remember doing trig myself and i remember taking out a factor instead of doing a quadratic and someone posted nooooooooooooooo with a funny picture of someone holding their head saying nooooooooooooo
Original post by thefatone
remember that

3tan2θ=13\tan ^2 \theta = 1

is the same as???

3(tanθ)2=1 3\left( \tan \theta \right)^2 = 1 ?????

Umm, yes. But it really doesn't matter in which order you deal with the coefficient lol. That's basic algebra. The key points here are quadratics and special angles.
Original post by thefatone
was it you?

i remember doing trig myself and i remember taking out a factor instead of doing a quadratic and someone posted nooooooooooooooo with a funny picture of someone holding their head saying nooooooooooooo


Probably not :tongue:
Original post by Student403
Probably not :tongue:


hmmm might have been TeeEm ...
Original post by Student403
For questions like these, your aim first is to isolate the trign(x) function so you can then take the nth root of both sides. So what you thought of doing first is correct

To extend this, in general you might not be able to 'isolate' the sin/cos function neatly. Anticipating harder questions you might get asked, you might have quadratic equations where the linear component is not zero eg. sin^2 - ((1+root3)/2)sin + (root3)/4. In general you're finding possible solutions of the quadratic, figuring out which of those solutions lie in the range of the trigonometric function and finding what values of x map to those solutions.
Original post by thefatone
was it you?

i remember doing trig myself and i remember taking out a factor instead of doing a quadratic and someone posted nooooooooooooooo with a funny picture of someone holding their head saying nooooooooooooo

Nevermind you were talking about something different than I thought.
(edited 8 years ago)
Original post by Unkempt_One
Nevermind you were talking about something different than I thought.


i found the thread which that happened check it out ^^^ a few posts up
Original post by Unkempt_One
To extend this, in general you might not be able to 'isolate' the sin/cos function neatly. Anticipating harder questions you might get asked, you might have quadratic equations where the linear component is not zero eg. sin^2 - ((1+root3)/2)sin + (root3)/4. In general you're finding possible solutions of the quadratic, figuring out which of those solutions lie in the range of the trigonometric function and finding what values of x map to those solutions.


Right :smile:




Nice find :P

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