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Circle

A circle passes through the points (0,2) and (0,8) and its centre lies on X=4
Find the equation of the circle.

Need help pls
Reply 1
Avatar for Zacken
Zacken
22
Original post by Aksa09
A circle passes through the points (0,2) and (0,8) and its centre lies on X=4
Find the equation of the circle.

Need help pls


Equation of circle centre (a,b)(a,b): (x−a)2+(y−b)2=r2(x-a)^2 + (y-b)^2 = r^2

You're given aa and you have two points to form two simultaneous equation in yy and rr
Original post by Zacken
Equation of circle centre (a,b)(a,b): (x−a)2+(y−b)2=r2(x-a)^2 + (y-b)^2 = r^2

You're given aa and you have two points to form two simultaneous equation in yy and rr


aww 2 mins too late
Reply 3
Avatar for Aksa09
Aksa09
OP
1
Original post by Zacken
Equation of circle centre (a,b)(a,b): (x−a)2+(y−b)2=r2(x-a)^2 + (y-b)^2 = r^2

You're given aa and you have two points to form two simultaneous equation in yy and rr


How do I form the two equations?
Reply 4
Avatar for Zacken
Zacken
22
Original post by Aksa09
How do I form the two equations?


Plug in the points for x,yx,y. So for example: (0,8)(0,8) gets you: (0−4)2+(8−b)2=r2(0-4)^2 + (8-b)^2 = r^2.
Original post by Aksa09
How do I form the two equations?


Sending a full solution to your inbox 1 sec
Reply 6
Avatar for KaylaB
KaylaB
20
Original post by TheRealDuck
Sending a full solution to your inbox 1 sec


That's not really helpful
Reply 7
Avatar for Aksa09
Aksa09
OP
1
Original post by Zacken
Plug in the points for x,yx,y. So for example: (0,8)(0,8) gets you: (0−4)2+(8−b)2=r2(0-4)^2 + (8-b)^2 = r^2.



Right got it, thank you!
Original post by KaylaB
That's not really helpful


You may be new and may not know me.

I go by the usernames
@ManLikeDuck
@ZackenLovesDuck
@DuckDucks
@StopBanningDuck
@Duckphysicsmaths

All of which accounts are currently banned. So, if I were you I'd take my ugly face out the Maths forum before I make it uglier

b i t c h
Reply 9
Avatar for B_9710
B_9710
18
Alternatively, you could find an equation of the perpendicular bisector of the chord between the 2 points given and use the fact that the centre is at x=4 to find the equation of the circle.
Reply 10
Avatar for KaylaB
KaylaB
20
Original post by TheRealDuck
You may be new and may not know me.

I go by the usernames
@ManLikeDuck
@ZackenLovesDuck
@DuckDucks
@StopBanningDuck
@Duckphysicsmaths

All of which accounts are currently banned. So, if I were you I'd take my ugly face out the Maths forum before I make it uglier

b i t c h


You are correct that I do not know you, it must be really hard for you to keep one stable account. So you'll probably being ducking (:teehee:) off soon anyway.
Have a quackers day:wink:
Original post by KaylaB
You are correct that I do not know you, it must be really hard for you to keep one stable account. So you'll probably being ducking (:teehee:) off soon anyway.
Have a quackers day:wink:


Wow. That was so bad... :unimpressed:

I've had enough of this site, I quit.
Original post by TheRealDuck
Wow. That was so bad... :unimpressed:

I've had enough of this site, I quit.


that's why when i tag @Zacken i get a duck as part of his username as an option aswell xD
Reply 13
Avatar for KaylaB
KaylaB
20
Original post by TheRealDuck
Wow. That was so bad... :unimpressed:

I've had enough of this site, I quit.


Whoops there goes another account
Original post by KaylaB
You are correct that I do not know you, it must be really hard for you to keep one stable account. So you'll probably being ducking (:teehee:) off soon anyway.
Have a quackers day:wink:


:rofl:
Original post by thefatone
that's why when i tag @Zacken i get a duck as part of his username as an option aswell xD


LOL

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