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Help on second order differential equations

image.jpg Could anyone possibly help me with the two questions I've circled from the AQA FP3 Textbook, theyre pretty similar. If anyone would be able to write out a full solution that would be fab because I'm unsure where I'm going wrong! Many thanks
(edited 8 years ago)
Reply 1
Avatar for Zacken
Zacken
22
Original post by Laurenknott1
image.jpg Could anyone possibly help me with the two questions I've circled from the AQA FP3 Textbook, theyre pretty similar


Have you already done the substitution? If not, then: dydt=dydx×dxdt\frac{dy}{dt} = \frac{dy}{dx} \times \frac{dx}{dt}.
Reply 2
Avatar for B_9710
B_9710
18
If y=ux then dydx=xdudx+u \displaystyle \frac{dy}{dx}=x\frac{du}{dx}+u
Now find d2ydx2 \frac{d^2y}{dx^2} by differentiating dy/dx with respect to x.

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