Edexcel FP1 Thread - 20th May, 2016

This might be a stupid question, but on question 1c of exercise 4D please, https://644625398389466aee00633223056f55519d5fbc.googledrive.com/host/0B1ZiqBksUHNYQWY1UWtNa0NRNU0/CH4.pdf why isn't x to xy linear, as I thought it would be since it's only to the power 1?! Thanks :smile:

Reply 42

Original post by economicss

This might be a stupid question, but on question 1c of exercise 4D please, https://644625398389466aee00633223056f55519d5fbc.googledrive.com/host/0B1ZiqBksUHNYQWY1UWtNa0NRNU0/CH4.pdf why isn't x to xy linear, as I thought it would be since it's only to the power 1?! Thanks :smile:

A linear transformation is linear if it satisfied

T(\lambda a + \mu b) = \lambda T(a) + \mu T(b)

where

a

and

b

are column vectors.

Obviously,

y \to x + xy

isn't.

Reply 43

Hi, please could anyone explain what is meant by 'orientation is reversed' on exercise 4h question 2c https://doc-00-0g-docs.googleusercontent.com/docs/securesc/tv01ac8rh9u7v3n9tei94valah3mgfnn/aogvugean6528vb2cdj3kn5f0ohumh82/1459684800000/01042298237316186224/02734711105213058970/0B1ZiqBksUHNYRkZmYTlpUmpNYXM Thanks :smile:

Reply 44

Original post by economicss

Hi, please could anyone explain what is meant by 'orientation is reversed' on exercise 4h question 2c https://doc-00-0g-docs.googleusercontent.com/docs/securesc/tv01ac8rh9u7v3n9tei94valah3mgfnn/aogvugean6528vb2cdj3kn5f0ohumh82/1459684800000/01042298237316186224/02734711105213058970/0B1ZiqBksUHNYRkZmYTlpUmpNYXM Thanks :smile:

Can't view the PDF for some reason.

Reply 45

NotNotBatman

20

Do the IAL F1 and IAL FP1 papers follow the same syllabus?

Reply 46

Original post by NotNotBatman

Do the IAL F1 and IAL FP1 papers follow the same syllabus?

More or less, I didn't really see any differences. Then again, I barely read the specification.

Reply 47

Ayman!

15

Original post by NotNotBatman

Do the IAL F1 and IAL FP1 papers follow the same syllabus?

Yes, minor differences such as knowing that a quadratic equation equation can be written as

x^{2}-\left ( \alpha +\beta \right )x+\alpha \beta = 0

and matrix rotations about any angle. That's about it, I think.

Reply 48

NotNotBatman

20

Original post by Zacken

More or less, I didn't really see any differences. Then again, I barely read the specification.

Thank you.

Original post by aymanzayedmannan

Yes, minor differences such as knowing that a quadratic equation equation can be written as

x^{2}-\left ( \alpha +\beta \right )x+\alpha \beta = 0

and matrix rotations about any angle. That's about it, I think.

Isn't the quadratic equation thing in FP1? It's the only method I've been taught although I do know how to use other methods.

Reply 49

Ayman!

15

Original post by NotNotBatman

Isn't the quadratic equation thing in FP1? It's the only method I've been taught although I do know how to use other methods.

It isn't compulsory knowledge on FP1 - questions can be done without this formula. However, many questions on IAL are based on this.

Reply 50

Original post by Zacken

Can't view the PDF for some reason.

Hi, sorry about the links, here's a pic of the question, I'm just not too sure by what they mean by 'the orientation is reversed' on part c? Thank you :smile:

Attachment not found

Hi, please could anyone explain 6c on this paper, how do we know that QP=I and in particular how do we know it's QP rather than PQ? Thanks :smile:

Attachment not found

Original post by economicss

...

Does reading this ( http://mathinsight.org/determinant_linear_transformation ) help?

Reply 53

Original post by economicss

...

1. Triangle

T

is transformed to

T'

by

P

. Triangle

T'

is transformed back to

T

by

P^{-1}

. The question has simply called

Q = P^{-1}

. Inverses satisfy

PP^{-1} = PQ = I

.

2. Inverses are commutative so

PP^{-1} = PQ = I = QP = P^{-1}P

. That is, it doesn't matter which order you pick here, either will work.

Reply 54

Original post by Zacken

Does reading this ( http://mathinsight.org/determinant_linear_transformation ) help?

Thank you, I think so, so is it saying that if one determinant is the negative of another determinant then the orientation of the second determinant is reversed compared to the original determinant? :smile:

Reply 55