F is a constant retarding force so surely f would be negative in the equation. However the markscheme indicates otherwise. Its positive f in the mark scheme.
F is a constant retarding force so surely f would be negative in the equation. However the markscheme indicates otherwise. Its positive f in the mark scheme.
You are getting confused. The force acts in whatever direction your acceleration acts. I am not sure what you are resolving here... your acceleration and force are 2 dimensional components already resolved in the horizontal (i) and vertical (j) direction. So resolving "to the right" as you have seeming shown, makes 0 sense. If you resolve to the right, all your j components disappear...
You are talking about F as though it is a number, it is a vector and it doesn't make sense to talk about "negative vectors" or "one vector is greater than 0" or along those lines. The technical reason for this is that the ordered pair of real numbers aren't well-ordered or don't possess a well-ordering. (lol sounds oxymoron, but oh well)
You are getting confused. The force acts in whatever direction your acceleration acts. I am not sure what you are resolving here... your acceleration and force are 2 dimensional components already resolved in the horizontal (i) and vertical (j) direction. So resolving "to the right" as you have seeming shown, makes 0 sense. If you resolve to the right, all your j components disappear...
You are talking about F as though it is a number, it is a vector and it doesn't make sense to talk about "negative vectors" or "one vector is greater than 0" or along those lines. The technical reason for this is that the ordered pair of real numbers aren't well-ordered or don't possess a well-ordering. (lol sounds oxymoron, but oh well)
I am so sorry but I am even more confused by what you just said. The equation is supposed to be f=ma. But since f is a retarding force in this question, it will act in the different direction to acceleration thus the unknown force will be negative. I don't get what you mean.
I am so sorry but I am even more confused by what you just said. The equation is supposed to be f=ma. But since f is a retarding force in this question, it will act in the different direction to acceleration thus the unknown force will be negative. I don't get what you mean.
No! F always acts in whatever direction acceleration acts. If F is a retarding force, that simply means your acceleration is a retardation. But your force still acts in the direction of acceleration.That's it. End of.
No! F always acts in whatever direction acceleration acts. If F is a retarding force, that simply means your acceleration is a retardation. But your force still acts in the direction of acceleration.That's it. End of.
The force in the question you've linked isn't the resultant force.
Newton's second law states that Fnet=ma and since m is a positive scalar, then Fnet has the same direction as a.
In the question in the video, F is just the variable given for a force, but that isn't the resultant force.
In this question, F is the resultant retarding force.
In any case - the video deals with one dimensional forces. Your question deals with two dimensional forces, "resolving" the way you have makes no sense.
The force in the question you've linked isn't the resultant force.
Newton's second law states that Fnet=ma and since m is a positive scalar, then Fnet has the same direction as a.
In the question in the video, F is just the variable given for a force, but that isn't the resultant force.
In this question, F is the resultant retarding force.
In any case - the video deals with one dimensional forces. Your question deals with two dimensional forces, "resolving" the way you have makes no sense.
How do you know that this is the resultant force? It doesn't say in the question
No, I have just realised that. So basically resultant force always acts in the same direction as a. But if F is only one force and there are other forces involved, it can move In the different direction to a?
No, I have just realised that. So basically resultant force always acts in the same direction as a. But if F is only one force and there are other forces involved, it can move In the different direction to a?
Yes, precisely.
But once you sum all the other forces involved, the sum is then the resultant force and moves in the direction of a.