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Order of Reaction Help! :)

Why is the answer D and not A?
And what do they mean "against the square of the concentration of a reactant ..?"
(edited 8 years ago)
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Original post by Adorable98
Why is the answer D and not A?
And what do they mean "against the square of the concentration of a reactant ..?"


hmmmm a very interesting question ...
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Adorable98
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Original post by charco
hmmmm a very interesting question ...


So you don;t know the answer?:frown:
Original post by Adorable98
So you don;t know the answer?:frown:


no, I don't know the question!
Original post by charco
no, I don't know the question!


I'm going to have a guess even though we don't know what's 'in the box'.

The answer is D because the reaction is second order with respect to the reactant in question and therefore is squared in the rate equation.

Your go!
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Adorable98
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Original post by TeachChemistry
I'm going to have a guess even though we don't know what's 'in the box'.

The answer is D because the reaction is second order with respect to the reactant in question and therefore is squared in the rate equation.

Your go!


I still don't get it.
Original post by Adorable98
I still don't get it.


Aha, an image has appeared ...

D is a straight line which shows direct proportionality between rate and the concept on the other axis.

This is only possible if

rate = k x [A]2

or

rate = k[A][ B]
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Adorable98
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Original post by charco
Aha, an image has appeared ...

D is a straight line which shows direct proportionality between rate and the concept on the other axis.

This is only possible if

rate = k x [A]2

or

rate = k[A][ B]


Oh, I see!! Thank you!!

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