I need time dilation help please?

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no it does not move diagonally which can be easily proven and i have already shown.

NO, it can be measured differently on a different planet by present standards contradiction.

No, it cant. the speed of light is universal.

As for the diagonal light path, prove it :smile:

Reply 61

Kyx

Original post by AlbertXY

The fact is a beam of light needs a medium such as smoke to be seen, the fact is beams of light is observe effect, the light off the sun is isotropic and it is a fact it is not opaque.

No it doesn't, actually. that is a common myth.

Reply 62

AlbertXY

Light can only be reflected diagonally off a mirrored surface.

Reply 63

AlbertXY

Original post by Kyx

No it doesn't, actually. that is a common myth.

That is strange, I have a laser, I can not see the laser beam in natural light or in the dark , the frequency is beyond my visual range , however when I blow smoke from my cigarette, the laser interacts with the smoke and I can see the laser beam.

It is not a myth I own a laser and have tried this several times.

Reply 64

Kyx

Original post by AlbertXY

Light can only be reflected diagonally off a mirrored surface.

And that is exactly what is happening

Original post by AlbertXY

And if the frequency was inside your visual range?

Reply 65

AlbertXY

Original post by Kyx

No, it cant. the speed of light is universal.

As for the diagonal light path, prove it :smile:

Please look at any object in your room, do you see any diagonal paths of light, it is whole.

There you go proven.

The speed of light may be universal, but if an observer disagrees on time then they also have to disagree on speed. That is the contradiction.

Reply 66

AlbertXY

Original post by Kyx

And that is exactly what is happening

And if the frequency was inside your visual range?

You observe that has spectral colour between 400-700nm.

Reply 67

AlbertXY

Original post by Kyx

And that is exactly what is happening

And the mirror is observer effect, placed and angled to an imaginary visual beam.

Reply 68

Kyx

Original post by AlbertXY

Please look at any object in your room, do you see any diagonal paths of light, it is whole.

There you go proven.

It depends on how you define 'diagonal'. Which plane you are referring to as the vertical and the horizontal. So yes, I see more diagonal than vertical or horizontal.

Original post by AlbertXY

The speed of light may be universal, but if an observer disagrees on time then they also have to disagree on speed. That is the contradiction.

No. There is no contradiction. They all agree on speed, but disagree on time. Therefore they disagree on distance too.

Reply 69

The-Spartan

Original post by AlbertXY

You think a student is a troll for questioning the integrity of the knowledge been presented to him?

No, you questioning this is actually very good of you. But to ignore certain facts, and respond with a very vague/random response completely tangential to the argument you are presented with is rather infuriating to try and have a discussion with. I will now wrap this up:

Here we have a spaceship with a mirrored floor and roof. Now:

\Delta t^{'}=\frac{d}{c} = \frac{2L}{c}

For the person in the spaceship, this is the change in time.
note this is a model, and we are tracking the photon from the clock
As above, the time frame for the person in the space ship is as we expect it. distance/velocity is time.
Now for the observer outside the spaceship. Again this is a model

According to our observer, the distance

D

has changed compared to the person in the spaceship. Using pythagoras we can calculate this:

D^2=L^2+(\frac{x}{2})^2

Where

x

is the change in the x axis due to

v

x=v \Delta t

So by this logic

\Delta t^{'}=\frac{2L}{c}

\Delta =\frac{2h}{c}

. Therefore,

L=\frac{c\Delta t^{'}}{2}

and

D=\frac{c\Delta t}{2}

Substituting these values into the first equation:

(\frac{c\Delta t}{2})^2=(\frac{c\Delta t^{'}}{2})^2+(\frac{v\Delta t}{2})^2

As such:

Unparseable latex formula:

\Delta t=\dfrac{\Detla t^'}{\sqrt{1-\frac{v^2}{c^2}}}

There you you, proved the theory of special relativity using elementary level maths and some situations.

(edited 8 years ago)

Reply 70

AlbertXY

Original post by Kyx

It depends on how you define 'diagonal'. Which plane you are referring to as the vertical and the horizontal. So yes, I see more diagonal than vertical or horizontal.

No. There is no contradiction. They all agree on speed, but disagree on time. Therefore they disagree on distance too.

NO, speed is d/t

You cant agree on speed without agreeing on time

t1=1s

t2=a shorter second

d/t1=299 792 458 m / s

d/t2=further

Reply 71

Kyx

Original post by AlbertXY

NO, speed is d/t

You cant agree on speed without agreeing on time

t1=1s

t2=a shorter second

d/t1=299 792 458 m / s

d/t2=further

Speed = distance over time

So, if speed = 1

Distance can equal 1 if time equals 1
Or distance can equal 2 if time equals 2

Reply 72

AlbertXY

Original post by Kyx

Speed = distance over time

So, if speed = 1

Distance can equal 1 if time equals 1
Or distance can equal 2 if time equals 2

Yes , the speed of light in a vacuum is an invariant, we both can agree that light travelling 1m in a vacuum is a constant, but we both have to agree that time is an invariant.

Reply 73

Alexion

Original post by AlbertXY

Nope, wrong.

If the frequency of the light were outside your visual range, it'd be an IR or UV light. Doesn't matter if it's passing through smoke or what, you wouldn't be able to see it.

Just doesn't reflect off of the thinly dispersed gases in the air, hence why you don't see the light unless it's passing through a smoke or pointed directly at your eyes. It's just directional hence why you don't see it most of the time. Light from the sun, however, is widely dispersed and hence reflects off just about everything around us.

Reply 74

Kyx

Original post by AlbertXY

Yes , the speed of light in a vacuum is an invariant, we both can agree that light travelling 1m in a vacuum is a constant, but we both have to agree that time is an invariant.

Reply 75

AlbertXY

Original post by Alexion

Ok, so then you can tell me the frequency of white light can you?

Reply 76

The-Spartan

Original post by AlbertXY

Ok, so then you can tell me the frequency of white light can you?

This statement proves your lack of understanding. White light is a combination of all of the frequencies in the VR.

Reply 77

Alexion

Original post by AlbertXY

Ok, so then you can tell me the frequency of white light can you?

Seriously...

White light is made up of a mixture of different wavelengths of light. Combining all the different components of the visible spectrum into one light source creates a light that appears to be white.

Pretty sure that Year 7s know this.