C1 Soloman Paper C question

Hey.
Im having trouble doing questions (iii) and (iv).

I was able to do part ii and express in the form (x + a)^2 + b
But i dont understand how to get the translation.
I was only able to do part (iv) by differentiation to find the gradient, then find the formula that way.
Thanks


https://a9497d7f220e174d38d014b2b1d86a68bedc42a8.googledrive.com/host/0B1ZiqBksUHNYNExoNEtSS1ViN2c/for-OCR/Solomon%20C%20QP%20-%20C1%20OCR.pdf

@Zacken help i have no idea what i'm doing either xD

since you already put $y=x^2-6x+11$ in the form (x + a)^2 + b $\left(x-3\right)^2 +2$ i'm seeing the only difference which i'm seeing between the 2 equation is a -6x , not sure what to say for transformation

tbh i did part 4 by differentiation aswell ^-^

See my post above.

We want to translate $y = x^2 + 2$ to $y = (x-3)^2 + 2$ so we basically want the bit in the bracket to change from $x$ to $x-3$.

i.e: if $f(x) = x^2 + 2$ then $f(x-3) = (x-3)^2 + 2$. What does the translation $f(x-3)$ mean?

For (iv) think about what happens to the tangent.

Thanks.
Does the f(x) for transformation follow a similar rule for stretches.
Is f(2x) a stretch scale factor 1/2 in the x direction?