I need time dilation help please?

I know , it is your present information that makes this so, it is not my contradiction, it is sciences contradiction.

The speed of light is the same for all observers, but if observers are disagreeing on the length of a second, they are disagreeing on the speed of light, they in their reference frame will record a different speed because they have a different length of a second than we have if they used the Caesium to record time and time events.

We both have to agree that the length of a second is an invariant or we have to disagree on speed. I do not thing we can disagree on speed.

no no no

Speed = distance over time. If they agree on speed, but not distance, then they must also disagree on time.

You can't disagree about a distance, I know d/t , that is the whole point.



d/t1=x

d/t2=x


+ve(c)=1s

-ve(c)=1s



t net difference = 0


now if t2 is different than t1 the speed will be measured different.

One second is invariant by definition, but observers in different reference frames record different numbers of seconds between the same events.

if time = 1 and distance = 1, speed = distance/time = 1/1 = 1

if time = 2 and distance = 2, speed = distance/time =2/2 = 1

You can't disagree about a distance, I know d/t , that is the whole point.



d/t1=x

d/t2=x


+ve(c)=1s

-ve(c)=1s



t net difference = 0


now if t2 is different than t1 the speed will be measured different.

You can't be understanding because you just said it. If your second is different you measure speed different.

No, you are considering it wrongly,



f time = 2 and distance = 1, speed = distance/time =?

You can't be understanding because you just said it. If your second is different you measure speed different.

The actual speed is the same, regardless of units. I could say that the speed of light is 3 blurgs, and I will always measure it as 3 blurgs NO MATTER WHAT!

I said the actual speed is the same, but according to observers with different rates of time, the measurement d/t is different.

lets assume that everyone has the same units for time and distance

Then the speed of light will ALWAYS be 3x10^8 m/s , no matter what

Yes if they all had our units of measurement.


However try considering what the speed would be if we all had a second that was half the rate, does the m/s then not double?

No, because you measure distance differently too.

That is irrelevant since the actual speed is not changing.

You can't disagree about a distance, I know d/t , that is the whole point.



d/t1=x

d/t2=x


+ve(c)=1s

-ve(c)=1s



t net difference = 0


now if t2 is different than t1 the speed will be measured different.

No, because you measure distance differently too.

NO, all observers would agree that a yard stick is a yard.

It is relevant when you consider who's defining the speed, are you to say that the speed of light we measure is even remotely correct ? how do you know it is even fast? fast relative to what?

The Universe defines the universe it is not of us to define speed to being absolute to a time frame made by us.


If you did the maths you would find that presently the speed of light is faster than time,

To clarify, you're doing the wrong calculation. Technically speed is the derivative of position with the respect to time, but over small enough changes in position we can approximate it as the change in position - distance - over the change in time. In this case assume $x$ is the position of light. Then

$c=\frac{\mathrm{d} x}{\mathrm{d}t} \approx \frac{\Delta x}{\Delta t}.$

In your notation, you can write this as

$c=\frac{d}{t}$.

Now consider two different observers in difference reference frames. The first observer, Alice, measures the speed of light to be $c$ and the distance and time to be $d_1$ and $t_1$ respectively. The second observer, Bob, also measures the speed of light to be $c$ (by the postulate of SR, as confirmed experimentally). He measures the distance and time to be $d_2$ and $t_2$. Where is the contradiction here?

$\frac{d_1}{t_1}=c=\frac{d_2}{t_2}$.

We only need $t_1=t_2$ if $d_1=d_2$, but this is manifestly not the case for different reference frames! There are infinitely many variations that leave the speed of light invariant. For example, if $d_2=2d_1$ and $t_2=2t_1$,

$\frac{d_2}{t_2}=\frac{2d_1}{2t_1}=\frac{d_1}{t_1}$

and there is no problem.

Exactly what the Michelson-morley experiment was trying to determine. The speed of light is 3x10^8 m/s relative to EVERYTHING!