The Student Room Group
Original post by AindowJ
Hello,

I was wondering if anyone could offer some guidance for part c of the attatched question. I understand that i must use the sum formula

S30= 12([2^2]^30 -1) / 3

But where do i go from here?

Thankyou in advance.


A hint. What is 12÷312 \div 3?
You can use one of your rules of indices to simplify (22)30(2^2)^{30}
Reply 2
Original post by Kvothe the arcane
A hint. What is 12÷312 \div 3?
You can use one of your rules of indices to simplify (22)30(2^2)^{30}


Yeah Ive just realised where I was going wrong. Thanks
Reply 3
How would i go about closing this thread?
Original post by AindowJ
How would i go about closing this thread?


You can't so I've closed it for you :smile:

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