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P(-1.34<z<1.60)

P(-1.34<Z<1.60) = P(Z<1.60) - P(Z>-1.34)

P(Z<1.60) - ....

How do I finish it off I understand that it is

P(Z<1.60) - (1-P(Z<1.34))

Could someone explain how to do the rearranging please.
Original post by L'Evil Wolf
P(-1.34<Z<1.60) = P(Z<1.60) - P(Z>-1.34)

P(Z<1.60) - ....

How do I finish it off I understand that it is

P(Z<1.60) - (1-P(Z<1.34))

Could someone explain how to do the rearranging please.


As in:

P(Z<1.60) +P(Z<1.34) -1?
Reply 2
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L'Evil Wolf
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Original post by Slowbro93
As in:

P(Z<1.60) +P(Z<1.34) -1?


Yes it is that, but I dont know how to proceed from this point:

P(-1.34<Z<1.60) = P(Z<1.60) - P(Z>-1.34)

I would like to understand that maths rearranging of it :smile:
Original post by L'Evil Wolf
Yes it is that, but I dont know how to proceed from this point:

P(-1.34<Z<1.60) = P(Z<1.60) - P(Z>-1.34)

I would like to understand that maths rearranging of it :smile:


Gonna draw it, give me two secs :smile:
Reply 4
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L'Evil Wolf
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Original post by Slowbro93
Gonna draw it, give me two secs :smile:


thanks b0ss
IMAG0324.jpg

I've basically drawn the whole process out, does this help :smile:

Original post by L'Evil Wolf
thanks b0ss
Reply 6
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L'Evil Wolf
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Original post by Slowbro93
IMAG0324.jpg

I've basically drawn the whole process out, does this help :smile:


omg I was messing up the symmetry part, thank you.

I will definitely draw out until I get more acquainted. Thanks for the time taken to upload etc.
Original post by L'Evil Wolf
omg I was messing up the symmetry part, thank you.

I will definitely draw out until I get more acquainted. Thanks for the time taken to upload etc.


No worries :h: I've always found diagrams a really nice way to represent certain concepts and given during my PhD I still use them :tongue:
Reply 8
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Zacken
22
Original post by L'Evil Wolf


I will definitely draw out until I get more acquainted. Thanks for the time taken to upload etc.


Keep drawing them even if you are acquainted.
Reply 9
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L'Evil Wolf
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Original post by Zacken
Keep drawing them even if you are acquainted.


great tip yeah, for S3 the graphical calc can do it but for stuff like STEP probably not :P
Reply 10
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Zacken
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Original post by L'Evil Wolf
great tip yeah, for S3 the graphical calc can do it but for stuff like STEP probably not :P


Ew. No, don't use a graph calc. Use pen and paper. :tongue:
Original post by Zacken
Ew. No, don't use a graph calc. Use pen and paper. :tongue:


Can you explain page 9. Q6.

By the same principle I get 0.8185 which is wrong it should be 1-ans.

Is it different to the other quesiton?
Reply 12
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Zacken
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Original post by L'Evil Wolf
Can you explain page 9. Q6.

By the same principle I get 0.8185 which is wrong it should be 1-ans.

Is it different to the other quesiton?


What question are you talking about? Page 9, Q6 what?
Original post by Zacken
What question are you talking about? Page 9, Q6 what?


https://771a1ec81340d97ae9ed29694f73dd633b1c7c70.googledrive.com/host/0B1ZiqBksUHNYV1BTbDkxWXZCVmc/CH1.pdf

Sorry
Reply 14
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Zacken
22
Original post by L'Evil Wolf


This is different because both P(something < blah) has blah being positive. In your previous question on this thread, you had blah being negative. So basically just do what the solution bank did. Sketch the normal graph, sketch the bit for X-Y < 16, and then < 13. Then you'll see why you need to subtract the two if you want just the bit inbetween them.
Original post by Zacken
This is different because both P(something < blah) has blah being positive. In your previous question on this thread, you had blah being negative. So basically just do what the solution bank did. Sketch the normal graph, sketch the bit for X-Y < 16, and then < 13. Then you'll see why you need to subtract the two if you want just the bit inbetween them.


Thank you this makes a lot of sense.
Reply 16
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Zacken
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Original post by L'Evil Wolf
Thank you this makes a lot of sense.


No problem.

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