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Competition - post a photo you've taken of nature >>

Polar coordinate help needed

image.jpgCould someone tell me if I'm on the right track or I am going off on a tangent
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Zacken
22
Original post by Hjyu1
image.jpgCould someone tell me if I'm on the right track or I am going off on a tangent
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Well, you have rr - this is your distance from the origin. To maximise the distance from the origin you need to maximise rr, hence, you want drdθ=0\frac{\mathrm{d}r}{ \mathrm{d}\theta } = 0.

You needn't expand rr out to do this - a simple application of the product rule from the initial expression would have done so.
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Hjyu1
OP
2
Original post by Zacken
Well, you have rr - this is your distance from the origin. To maximise the distance from the origin you need to maximise rr, hence, you want drdθ=0\frac{\mathrm{d}r}{ \mathrm{d}\theta } = 0.

You needn't expand rr out to do this - a simple application of the product rule from the initial expression would have done so.


Omg I can't believe I didn't see that that's like core 1 work. Cheers hopefully this comes in the real exam
Reply 3
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Zacken
22
Original post by Hjyu1
Omg I can't believe I didn't see that that's like core 1 work. Cheers hopefully this comes in the real exam


:biggrin:

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