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fluid mechanics

I don't know where else to post this


From measurements taken on the variation of pressure with depth in a liquid, it was found that, on a certain day, 2m below the surface of a given liquid, the absolute pressure was 1.17 x 105N/m2, while at a depth of 5m the absolute pressure was 142kN/m2. Find a) the relative density of the liquid


what formula can i use
Original post by cushticwarrior
I don't know where else to post this


From measurements taken on the variation of pressure with depth in a liquid, it was found that, on a certain day, 2m below the surface of a given liquid, the absolute pressure was 1.17 x 105N/m2, while at a depth of 5m the absolute pressure was 142kN/m2. Find a) the relative density of the liquid


what formula can i use


P=ρgh P=\rho gh
Original post by langlitz
P=ρgh P=\rho gh


I have tried this already.

1x10^5/(9.81*2)=5963 This is not the answer given. Do you know what I am doing wrong
Original post by cushticwarrior
I have tried this already.

1x10^5/(9.81*2)=5963 This is not the answer given. Do you know what I am doing wrong


What's the given answer?
Original post by langlitz
What's the given answer?


0.8 something, relative density.
Original post by cushticwarrior
0.8 something, relative density.

You need to use the difference in pressure and the difference in height: ΔP = ρgΔh
(edited 7 years ago)
Thank you!

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