The Student Room Group

Differential Equations

Can someone check my working on this question please

http://imgur.com/a/ZMXsx
Reply 1
tao =/= t
Reply 2
Original post by iish
tao =/= t


Why not? It's seconds, right?
Reply 3
Original post by Naga7o
Why not? It's seconds, right?


What? tt is time. τ=Vq\tau = \frac{V}{q}
Reply 4
Original post by Zacken
What? tt is time. τ=Vq\tau = \frac{V}{q}


V/q = volume/volumetric flow rate = time?
Reply 5
Original post by Zacken
What? tt is time. τ=Vq\tau = \frac{V}{q}


The units of tau is seconds but that doesn't imply it's equal to t, it doesn't even imply it's a variable. In fact, the question is extremely poorly worded, I don't know if V is the initial volume or the volume as a function of time.
Reply 6
Original post by oShahpo
The units of tau is seconds but that doesn't imply it's equal to t.


Yeah, that's what I'm saying. :tongue:
Reply 7
Original post by Zacken
Yeah, that's what I'm saying. :tongue:


Quoted the wrong person :colondollar: sorry :biggrin:
Reply 8
Original post by Naga7o
V/q = volume/volumetric flow rate = time?


V is the volume as a function of time, then Volume / Volumetric flow = time if and only if the initial volume is zero. Otherwise their will be a constant.
Reply 9
Original post by oShahpo
V is the volume as a function of time, then Volume / Volumetric flow = time if and only if the initial volume is zero. Otherwise their will be a constant.


Would this approach be correct then?

http://imgur.com/4jbzWJz
Original post by Naga7o
Would this approach be correct then?

http://imgur.com/4jbzWJz


Between 0 and t0 C0 is a function of t, thus you haven't really separated the variables.
Your solution, I think, is correct for t>t0, for T<T0, solve this differential equation
dC/dT + C = alpha/T0 *t
This is a first differential equation that can be easily solved by finding the integrating factor.
(edited 7 years ago)
Reply 11
Original post by oShahpo
Between 0 and t0 C0 is a function of t, thus you haven't really separated the variables.
Your solution, I think, is correct for t>t0, for T<T0, solve this differential equation
dC/dT + C = alpha/T0 *t
This is a first differential equation that can be easily solved by finding the integrating factor.


What happened to tau?
Original post by Naga7o
What happened to tau?


It should be there, I made a mistake. Sorry.

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