Read this and was wondering why you were saying mum before and mum after.
Anyways, vectors is slightly awkward here, let's resolve instead (which is almost the same thing as vectors)
If we consider only horizontal motion, we get:
Impulse = change in momentum. The horizontal component of impulse is
12.5sinα pointing to the left.
The speed of B horizontally is (let's say v):
The
12.5sinα=0.25v−0.25(−30) where we use - since the ball is moving 30 metres per second opposite to the impulse and we gave impulse a +12.5 sinalpha.
Anyways, since
sinα=0.6 we have:
12.5(0.6)=0.25v+7.5⟺7.5=0.25v+7.5, this gives
v=0.
So there is no horizontal component of B, thank god, that makes life simple!
Now - let's consider vertical motion:
This gives us:
12.5cosα (impulse acts upwards)
And the change in momentum is
0.25u−0 (u is our vertical speed) and there is no vertical motion previous to the impulse.
So
12.5cosα=0.25u⟺u=4×12.5×0.8=40. So the speed is 40 vertical and 0 horizontal, and hence 40 overall.
And from this, since the 40 overall is acting vertically upwards, then the direction of travel of B is "perpendicular to the original direction". i.e: it went from pure horizontal to pure vertical.