Hey guys i'm stuck on this question (1 +√ x )^3 my method is 3C0 x (1)^3 x (√x)^0 = 1 x 1 x 1 = 1 3C1 x (1)^2 x (√x)^1 = 3 x 1 x √x = 3√x 3C2 x (1)^1 x (√x)^2 = 3 x 1 x x^2 3C3 x (1)^0 x (√x)^3 = 3 x 1 x √x . x^3
What I'm struggling to understand is why (√x)^2 is 2√x rather than x
Hey guys i'm stuck on this question (1 +√ x )^3 my method is 3C0 x (1)^3 x (√x)^0 = 1 x 1 x 1 = 1 3C1 x (1)^2 x (√x)^1 = 3 x 1 x √x = 3√x 3C2 x (1)^1 x (√x)^2 = 3 x 1 x x^2 3C3 x (1)^0 x (√x)^3 = 3 x 1 x √x . x^3
What I'm struggling to understand is why (√x)^2 is 2√x rather than x
Hey guys i'm stuck on this question (1 +√ x )^3 my method is 3C0 x (1)^3 x (√x)^0 = 1 x 1 x 1 = 1 3C1 x (1)^2 x (√x)^1 = 3 x 1 x √x = 3√x 3C2 x (1)^1 x (√x)^2 = 3 x 1 x x^2 3C3 x (1)^0 x (√x)^3 = 3 x 1 x √x . x^3
What I'm struggling to understand is why (√x)^2 is 2√x rather than x
3rd line = 3 x 1 x X =3X 4th line = 3 x 1 x X^(3/2) = 3X^(3/2)