i wrote 1200 i didnot write the sign and in the graph i forgot the sign will i lose any mark
Idk,Maybe you will,Maybe you won't,Firstly it was an enthalpy change question so usually a sign is included but the question WAS about combustion so MAYBE you will gain a mark.
I feel like many of us messed up the carbonate ion (and therefore the equation) - I mean I did. Don't worry, hopefully the grade boundaries won't be too high. Good luck with your other exams ))
But the heat loss will make it less exothermic not more exothermic - so it won't be valid?
You are correct. The heat loss was a valid statement because the students who performed the experiment got a value which was higher than the actual value (less exothermic)
You are correct. The heat loss was a valid statement because the students who performed the experiment got a value which was higher than the actual value (less exothermic)
What did you guys get for the reason why less of F will be produced?
According to Markovnikov's rule the hydrogen from hydrogen halide attaches to the carbon atom in double bond that already has more no of hydrogens in the double bond. So 2 iodo hexane is the major product while F was 1 iodo hexane.
What did you guys get for the reason why less of F will be produced?
I don't remember exactly what the question was,But I linked the Major product and the structure of F,The Major product is favoured so more of it is produced. My actual answer was something like 'F is not a major product as blah less no. H blah C atom'. I think I could've expanded that.
What you said was correct. But the statement itself was valid.
Wait I hope I didn't read the question wrong - the original value they gave was much less exothermic than the actual value later on right? So heat loss will will make it less exothermic not more exothermic - which was the actual value, so not valid?
Wait I hope I didn't read the question wrong - the original value they gave was much less exothermic than the actual value later on right? So heat loss will will make it less exothermic not more exothermic - which was the actual value, so not valid?
The value student got was -800 kJ/mol While the Data booklet value was -1367.3 kJ/mol
I don't remember exactly what the question was,But I linked the Major product and the structure of F,The Major product is favoured so more of it is produced. My actual answer was something like 'F is not a major product as blah less no. H blah C atom'. I think I could've expanded that.
The answer to that was : The intermediate carbocation is a primary carbocation.
The value student got was -800 kJ/mol While the Data booklet value was -1367.3 kJ/mol
Yes exactly so the actual value is more exothermic. And therefore when the temperature change will decrease it is less exothermic and it would make the student's value even less exothermic (so a bigger percentage error). And that's why I said it's not valid.
Yes exactly so the actual value is more exothermic. And therefore when the temperature change will decrease it is less exothermic and it would make the student's value even less exothermic (so a bigger percentage error). And that's why I said it's not valid.