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Edexcel Unit 3 (IAL): Exploring Physics, WPH03 (11th May 2016)

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Grade boundary will definitely be high.

How was your graph? I averaged my points and mine was through the origin.

Resistivity value was around I guess 1.1*10^-6 i think?

I read the vernier calliper and got the answer as A (dont remember what it was)

Reply 101

Haamoo7

Original post by SaadKaleem

Yeah I got around the same for my graph too.

I messed up on the vernier caliper one and put 10.7 as my answer. Fu*k!

I hope the grade boundaries arent too high, as I'm almost certain that I've made numerous silly mistakes.

Reply 102

iWant.A

when will we have a full mark scheme?

Reply 103

Haamoo7

Original post by iWant.A

when will we have a full mark scheme?

An official one? Next year when it gets released.
In terms of an unofficial one, when someone is bothered enough to come up with an unofficial markscheme.

Reply 104

wima3109

Original post by SaadKaleem

i got 2.24x10^-6............what was your gradient???????????

Reply 105

tejsanghavi

did anyone get their gradient as 4.5?I made a major error.... i used the diameter on its own as area. how much do you guys think ill get out of 4?For keeping current constant i mentioned using a power pack set at 0.11A. Any chance its correct?

Reply 106

Blazyy

Original post by tejsanghavi

To keep current constant, you need to use a variable resistor.

Reply 107

SaadKaleem

Original post by wima3109

i got 2.24x10^-6............what was your gradient???????????

Around 4 decimal something, don't exactly remember.

Original post by tejsanghavi

Yes I got around that, probably quoted in 3 s.f though. I think you'll get 1 mark only for quoting the formula.

For keeping current constant, I mentioned that as you increase the length (The resistance is proportional to it) so you need to increase the voltage with the same ratio, to keep the current constant in the circuit.

Reply 108

wima3109

to keep current constant i put use an EHF power supply

Reply 109

methrian

so is a variable resistor correct? to keep the current constant
I wrote the same thing :smile:

and what did u guys write for the last question? why the value is different

Reply 110

iWant.A

Change in the temperature in the circuit

Reply 111

iWant.A

Also to find the refractive index i wrote that the student must plot a graph of sin i against sin r and the refractive index will be the gradient

Reply 112

tejsanghavi

Original post by wima3109

to keep current constant i put use an EHF power supply

I mentioned using a power pack set at 0.11A. is it the same thing? any doubt on your answer?

Reply 113

faseeh1999

Original post by tejsanghavi

I got 4.58 pretty close to you..

Reply 114

faseeh1999

Original post by Blazyy

To keep current constant, you need to use a variable resistor.

.
Yayyy I wrote variable resistor :smile:

Reply 115

wenogk

Original post by iWant.A

Also to find the refractive index i wrote that the student must plot a graph of sin i against sin r and the refractive index will be the gradient

I wrote plot a sin r (y-axis) against sin i (x-axis) and find the inverse of the gradient as the incident angle is what we are changing hence is the independent variable and has to go to the x axis.

Reply 116

Imperion

Original post by Haamoo7

For IAL they're constant?

Not a bad paper overall ;o

Reply 117

EUSHA

What was the vernier caliper one?
and what's the answer to the question where they ask how setup was in timing the can as it rolled down a slope in no.6c)??
thanks in advance! :biggrin: