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Nuclear Radius Equation R = R0 A^(1/3)

If using the nuclear radius equation:

R = R0 A^(1/3)

as shown half-way down this page:
http://en.wikipedia.org/wiki/Atomic_nucleus

r0 = 1.25 fm = 1.25 × 10−15 m

Is this value for r0 always this value, irrespective of the material in question? For example, if it was gold, or some other material?

Thanks
Reply 1
Avatar for teachercol
teachercol
9
Yes - its the average radius of a nucleon.

There are different figures used depening how r has been measured - the density of a nucleon doesnt drop as a step function.
Reply 2
Avatar for little pixie
little pixie
OP
12
Thank you teachercol !
Reply 3
Avatar for CALI1198
CALI1198
5
I know this is an old thread but I'm a bit confused.

My textbook tells me its 1.05fm but my cgp textbook quotes it as 1.4fm. Would I gain the marks if i used either number?
Original post by CALI1198
I know this is an old thread but I'm a bit confused.

My textbook tells me its 1.05fm but my cgp textbook quotes it as 1.4fm. Would I gain the marks if i used either number?


It's an empirically determined constant and is usually quoted to be between 1.2 and 1.5fm
Reply 5
Avatar for CALI1198
CALI1198
5
Original post by natninja
It's an empirically determined constant and is usually quoted to be between 1.2 and 1.5fm

Thanks. I plan to just stick to 1.25 unless told otherwise

Sent from my One using Tapatalk
Original post by CALI1198
Thanks. I plan to just stick to 1.25 unless told otherwise

Sent from my One using Tapatalk


To be fair, even using 1fm would probably be good enough as it is an approximation anyway
I know this is an old thread but are we expected to memorise the value of R0?

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