Quick question quick answer

Find dx
dy

y = 2X^3 - 3X^2 + 4X - 6

Also, am I the only one who really enjoys surds ?

Yes I know these aren't surds, inb4 so smart@ss says it. Thanks for the help, will loiter to pay it forward.

Firstly I think you mean dy/dx

and secondly like the person above me said what's the issue ?

dy/dx = 6X^2 - 6X + 4

Nope, i don't get it. I know it's something incredibly dumb that I'm missing, but, I can no brain that at the moment.

Nope, i don't get it. I know it's something incredibly dumb that I'm missing, but, I can no brain that at the moment.

Saying "i don't get it" is extremely useless. What particular bit don't you get? What's the issue? What have you tried?

Don't worry man I got you on this,

basically what I did was the differentiation rule ( you can take all the values out separately if it makes it easier for you to understand)

So the f(x) = 2X^3 - 3X^2 + 4X - 6

So you have the value of 2X^3, - 3X^2 , 4X and - 6

Now what you basically do is times the indices to the coefficient

so in this case I did 2 x 3, 3 x 2 and 4 x 1 ( I ignore the 6 as it doesn't have a variable and isn't a coefficient )

Then once I do that I subtract the indices by -1 so the ^3 becomes ^2, the ^2 (on 3X) becomes ^1 (so just X) and the X is removed from the 4X as it was basically (4X^1)

So my answer then is dy/dx = dy/dx = 6X^2 - 6X + 4