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Quadratic inequalities

So I have this question:


For b, I got p = 3-2√2 and 3+2√2. The mark scheme says the answer is:

p<3-2√2 or p>3+2√2

How do I know whether to put "or" or just write it like: 3+2√2 < p < 3-2√2 ?
Reply 1
Original post by кяя
So I have this question:

For b, I got p = 3-2√2 and 3+2√2. The mark scheme says the answer is:

p<3-2√2 or p>3+2√2

How do I know whether to put "or" or just write it like: 3+2√2 < p < 3-2√2 ?


You sketch the graph of p26p+1>0p^2 - 6p +1 > 0. Always sketch the graph, it doesn't need to be elaborate, just a U if the number in front of p^2 is positive and an upside down u it's negative.

Label the roots (where it cuts the axis) as your values.



Then you know that you want the graph to be >0, that is, above the p-axis. That's precisely the region that >second root and <first root.

Had it asked you for p^2 - 6p + 12 < 0, then you would want the region where the graph is under the x-axis which is in between the two roots, so 3 - sqrt(blah) < p < blah
Reply 2
Original post by Zacken
so 3 - sqrt(blah) < p < blah


:lol:
Reply 3
Original post by Alexion
:lol:


I got lazy towards the end. :tongue:
Original post by кяя


How do I know whether to put "or" or just write it like: 3+2√2 < p < 3-2√2 ?


Well the value on the left is greater than the value on the right, so that can't be correct.
Reply 5
Oh, I get it now. Thanks guys!! :smile: repped
Reply 6
Original post by кяя
Oh, I get it now. Thanks guys!! :smile: repped


No problem. :smile:

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