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AQA A Level Maths Core 1 - 18th May 2016 [Exam Discussion]

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Original post by ZT006409
no it was 9


The length AC was. The length CT was 9.

circle2.png
Original post by beanigger
thats wrong because we didnt originally complete the square
you are jumping to the second half of completing the square which is not what we were asked to do

completing the square
1) make sure coefficient of x^2 = 1
2) take out a factor of x from x^2 and bx
3) half the coefficient of bx
4) raise the new b and x to the power of 2
5) and then minus the square of the new b

you jumped to number 5 without doing all the before, how is that right
thats like doing this

y=x^3 +5x
dy/dx = 3x^2
you see where its wrong? The 5x is differentiated twice this is the same as what u done, jumped the gun


doont ever tell me im wrong , you beanhead
Original post by medicine71012
How did u find the coordinates of B


in the question they said AB was diameter of circle
so that means C was the midpoint of line AB
we have co ordinates of C
to work out midpoint (x1+x2)/2 and (y1+y2)/2

make the co ordinates of C equal to the respective formula for x and y and u get the value of B
Original post by WhiteTigerKURD
I got 11.25


SAME :smile:
Integration question seems to be 11.25 then as that is also what I got.
And KittyKat97, yes it is 45 lol.
Original post by money-for-all
doont ever tell me im wrong , you beanhead


lol
Original post by timtjtim
take a look at my image i've attached for you bruv. As you can see, you go to the side 7 and you're uppin and downin by 4 - well 4^2 + 7^2 = 16+49 = 65.

I've attached a second image, of desmos, showing that the only circle which intersects a has radius of 65 - waddya think? If you're still not getting the hang of these circles, feel free to drop me a private message bro.


ooooooo , check you fancy pants , desmos and ****, you still clapped tho
Original post by iamastudent123
I got 243/12 for first part?


It is the same 243/12 = 81/4 (divided by 3)
Original post by beanigger
in the question they said AB was diameter of circle
so that means C was the midpoint of line AB
we have co ordinates of C
to work out midpoint (x1+x2)/2 and (y1+y2)/2

make the co ordinates of C equal to the respective formula for x and y and u get the value of B


Ahhhhh is that the only way and how many marks?
Original post by medicine71012
How did u find the coordinates of B


The line AB is the diameter of the circle.

We know that A to C is sqrt(65). We also know that this is the radius.

Hence, C is the midpoint between A and B.
Original post by medicine71012
Ahhhhh is that the only way and how many marks?


that is the way i done it i am not sure of any other ways sorry xd and it was worth 2 marks
that's what i got as well
I blanked on the question of the circles where the coordinates of B were asked.
Last minute i realised all i had to was midpoint
I thought it was actually horrendous. Missed out 5,6 and part of 7. If I get 100% of what I did I'll get a low B/C. Defo resorting next year :s-smilie:
Original post by christineedaley
How did you guys find the value of k? (in questions 6 i think) I just guessed and put k=4 :/


well there were two questions involving k, the one with the circles and k was the radius squared, and the other where coordinates where you simply had to substitute the coordinates in ur equation.

the one with the circles was root 65
and the other was -30
Original post by money-for-all
oh my days tim tim , you are clapped fam.

Why you bringing pythagoras into this ? Thats just the same as saying you use logarithms to integrate...


You had to use pythagoras to work it out. Radius=root 65

Therefore,
K=65 :smile:
Original post by musslih
OH MY GOSH that was the hardest paper...... it was kindof harder than Past Year Papers.... Can we discuss some stuff here?

1. Question 5b, what was your coordinate of B?

2. For the integration question ( was it Q7? or 8?)
a)what was your x- coordinate for Q?
b)what was your equation for the tangent at P?
c) what was your area under the graph? (referring to the same qn)


1. the coordinates were 12, -7 i think or something like that
2a) x coordinate was -5/4
b)y= 32x+40
c) that was 135/12 = 45/4 = 11.25
Sorry but Tim's right
Original post by Poppy1098
I also got root 34

you had to use pythagaros which got you route 64
Original post by money-for-all
ooooooo , check you fancy pants , desmos and ****, you still clapped tho


Naw bruv, not into the alcohols and that kinda stuff - yolo remember. I'm glad the desmos image helped you. Feel free to PM me if you have more questions.

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