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I need help with a maths question

ImageUploadedByStudent Room1463614688.474167.jpg the power is to -1/2 and you have to simplify it, i dont understand what to do with the powers, could someone explain?


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Reply 1
Avatar for Luke4857
Luke4857
1
You could start with multiplying everything by the power, that's what you normally do for indices
Reply 2
Avatar for Zacken
Zacken
22
Original post by ksj.11
ImageUploadedByStudent Room1463614688.474167.jpg the power is to -1/2 and you have to simplify it, i dont understand what to do with the powers, could someone explain?


Posted from TSR Mobile


Okay, so (ab)−1=ba\left(\frac{a}{b}\right)^{-1} = \frac{b}{a}.

So: (64x625y2)−1/2=(25y264x6)1/2=25y264x6=25y264x6=25y264x6=⋯\displaystyle \left(\frac{64x^6}{25y^2}\right)^{-1/2} = \left(\frac{25y^2}{64x^6}\right)^{1/2}= \sqrt{\frac{25y^2}{64x^6}} = \frac{\sqrt{25y^2}}{\sqrt{64x^6}} = \frac{\sqrt{25}\sqrt{y^2}}{\sqrt{64}\sqrt{x^6}} = \cdots
Reply 3
Avatar for ksj.11
ksj.11
OP
3
Original post by Zacken
Okay, so (ab)−1=ba\left(\frac{a}{b}\right)^{-1} = \frac{b}{a}.

So: (64x625y2)−1/2=(25y264x6)1/2=25y264x6=25y264x6=25y264x6=⋯\displaystyle \left(\frac{64x^6}{25y^2}\right)^{-1/2} = \left(\frac{25y^2}{64x^6}\right)^{1/2}= \sqrt{\frac{25y^2}{64x^6}} = \frac{\sqrt{25y^2}}{\sqrt{64x^6}} = \frac{\sqrt{25}\sqrt{y^2}}{\sqrt{64}\sqrt{x^6}} = \cdots


It wont let me view the rest of your answer after you flipped the numbers 25 at top and 64 at bottom 😣😣


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Reply 4
Avatar for Zacken
Zacken
22
Original post by ksj.11
It wont let me view the rest of your answer after you flipped the numbers 25 at top and 64 at bottom 😣😣


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You'll need to open it in a browser or on a desktop.

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