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Anyone wanna revise maths

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Original post by mariam687
alright imma let u kno

but i doubt it'll work, its not skypes problem, its the laptop tbh

but yh imma let u kno dw


Okay sure!
Original post by junayd1998
Yeah you got skype we doing in a group so we can all help each other


Whats ur skype? ill add you
Does anyone know where the predicted 2016 edexcel paper is?
Original post by SmallTown
Does anyone know where the predicted 2016 edexcel paper is?


Yes i do! :smile:
Original post by _Xenon_
Yes i do! :smile:


tell me / send me the link plz
Original post by ShahbazKHAN
tell me / send me the link plz


I wouldn't rely on them unless you've revised absolutely everything?
Original post by _Xenon_
I wouldn't rely on them unless you've revised absolutely everything?


yh i have
I can join, I'm doing A level though
Original post by ShahbazKHAN
yh i have


OK good luck.

1H QUESTION PAPER: http://www.mathsgenie.co.uk/resources/june2016p1.pdf
1H SOLUTIONS: http://www.mathsgenie.co.uk/resources/june2016p1ans.pdf

Once you've done these try the ones by OnMaths which can be done ONLINE.
add me Guys
Original post by kandaman
add me Guys


Drop your skype name
Reply 31
I need help with this image.jpg
Original post by Rajive
I need help with this image.jpg


Well we were told that the perimeter of rectangle is 28cm. So if we denote the length of the rectangle as y, then the perimeter would be the whole distance around the rectangle. Which would be 2x + 2y.

We now that the perimeter is 2x +2y, therefore we can equate this to 28 as we were told that the perimeter of the rectangle is 28cm.

Equation 1:

2x + 2y =28

Dividing through by two. Therefore x + y = 14. Then we can rearrange the equation making y the subject. Which gives us, y = 14 - x


Another fact the we now is that the width is xcm and the length of the diagonal is 12 cm. As we have let the length of the rectangle equal to y, we can now you Pythagoras which gives us x^2 + y^2 = (12)^2. Which simplifies to x^2 +y^2 =144

We now have two equations.

Equation 1: x + y = 14 and Equation 2: x^2 + y^2 =144. I would now like you to solve these simultaneous equations. Hope this helped!
Reply 33
Original post by phat-chewbacca
Well we were told that the perimeter of rectangle is 28cm. So if we denote the length of the rectangle as y, then the perimeter would be the whole distance around the rectangle. Which would be 2x + 2y.

We now that the perimeter is 2x +2y, therefore we can equate this to 28 as we were told that the perimeter of the rectangle is 28cm.

Equation 1:

2x + 2y =28

Dividing through by two. Therefore x + y = 14. Then we can rearrange the equation making y the subject. Which gives us, y = 14 - x


Another fact the we now is that the width is xcm and the length of the diagonal is 12 cm. As we have let the length of the rectangle equal to y, we can now you Pythagoras which gives us x^2 + y^2 = (12)^2. Which simplifies to x^2 +y^2 =144

We now have two equations.

Equation 1: x + y = 14 and Equation 2: x^2 + y^2 =144. I would now like you to solve these simultaneous equations. Hope this helped!


Wooow that makes a lot of sense.

I feel scared because I wouldn't know to do this in the exam...

Thanks though
Original post by Rajive
Wooow that makes a lot of sense.

I feel scared because I wouldn't know to do this in the exam...

Thanks though
I suggest you do it again in a few days then!
Reply 35
Original post by phat-chewbacca
I suggest you do it again in a few days then!


I got 7+_ root 23?
Anyone got the aqa Linear B predicted paper?
anyone doing igcse edexcel maths ?
Original post by mariam687
alright imma let u kno

but i doubt it'll work, its not skypes problem, its the laptop tbh

but yh imma let u kno dw


Any luck with your skype? If not you can PM questions.
Original post by salty670
anyone doing igcse edexcel maths ?


Sorry GCSE Edexcel

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