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Charge and Field

Please could someone work out the answer to the electric potential in Q 4) c) - I got the rest of it right, but my answer was different to the book for that part
2016-05-20 20.19.46.jpg332.1KB
Reply 1
Avatar for pri12321
pri12321
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What did the book get, and what did you get?
Reply 2
Avatar for TSR George
TSR George
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Original post by TheBride
What did the book get, and what did you get?


I got 2500V, whereas the book got 5000V
The Pd across the gap is 10KV. So halfway the PD will be half of that which is 5000V
Reply 4
Avatar for TSR George
TSR George
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Original post by SirRaza97
The Pd across the gap is 10KV. So halfway the PD will be half of that which is 5000V


Oh okay, thank you!
I used the electric field strength from V/d and multiplied by r to get Velec. Is this an incorrect method?
Yes you can use that equation! Field Strength is the same but the distance r is half
Reply 6
Avatar for TSR George
TSR George
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Original post by SirRaza97
Yes you can use that equation! Field Strength is the same but the distance r is half


Aha maybe that's where I went wrong! Thank you :smile:

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