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C2 logs

paper
https://b940eb267c31463d4d23ccfd3105c3b78e5616c6.googledrive.com/host/0B1ZiqBksUHNYUnQzSHRkZ3JoNGs/for-Edexcel/Solomon%20E%20QP%20-%20C2%20Edexcel.pdf
answers
https://b940eb267c31463d4d23ccfd3105c3b78e5616c6.googledrive.com/host/0B1ZiqBksUHNYUnQzSHRkZ3JoNGs/for-Edexcel/Solomon%20E%20MS%20-%20C2%20Edexcel.pdf
Question 8 part b
i don't understand why a=1.06

Edit:actually the title may wanted to be changed O.O i don't know how to do that either xD
(edited 7 years ago)
Reply 1
Avatar for Zacken
Zacken
22
Original post by thefatone


The first term is 1.06 in the brackets? That's what a is? The first term?
Reply 2
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thefatone
OP
6
Original post by LastMinReviseGuy
You know how you times a value by 1, which gives you 100%. That 1.06 is basically adding 6 % of the a to A.


Original post by Zacken
The first term is 1.06 in the brackets? That's what a is? The first term?


no not the 1.0681.06^8

the 1.06 which is outside the bracket on the top just behind the 1.0681.06^8

I'm sure the first term is £500

Edit:never mind i got it
(edited 7 years ago)
Reply 3
Avatar for Zacken
Zacken
22
Original post by thefatone
no not the 1.0681.06^8

the 1.06 which is outside the bracket on the top just behind the 1.0681.06^8

I'm sure the first term is £500


You have: 500(1.06+⋯+1.068)500(1.06 + \cdots + 1.06^8) . You sum up the bit inside the brackets only. You ignore the 500 for the moment, sum the bit inside the brackets which is a geometric series with first term 1.061.06 and then multiply the sum by 500. But for the moment, you are only summing the bit inside the brackets and ignoring the factor of 500, you'll multiply that in later.
Reply 4
Avatar for thefatone
thefatone
OP
6
Original post by Zacken
You have: 500(1.06+⋯+1.068)500(1.06 + \cdots + 1.06^8) . You sum up the bit inside the brackets only. You ignore the 500 for the moment, sum the bit inside the brackets which is a geometric series with first term 1.061.06 and then multiply the sum by 500. But for the moment, you are only summing the bit inside the brackets and ignoring the factor of 500, you'll multiply that in later.


Right got that bit sorted but how do i go about doing part c???
500(1.06) = a
2nd would be 500(1.06+1.06^2)

a is 500(1.06)
Dunno why it says 1.06.

Need to go over logs again.
Reply 6
Avatar for Zacken
Zacken
22
Original post by LastMinReviseGuy
500(1.06) = a
2nd would be 500(1.06+1.06^2)

a is 500(1.06)
Dunno why it says 1.06.

Need to go over logs again.


See my post.
So r=1.06
and a also =1.06

?
Reply 8
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Zacken
22
Original post by thefatone
Right got that bit sorted but how do i go about doing part c???


By thinking. It's literally the same as the previous part with different numbers.
Reply 9
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thefatone
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6
Original post by Zacken
By thinking. It's literally the same as the previous part with different numbers.


so i just do this then?

500×1.005[1.0058−1]1.005−1\dfrac{500\times1.005[1.005^8 -1]}{1.005-1}???
Reply 10
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Zacken
22
Original post by thefatone
so i just do this then?

500×1.005[1.0058−1]1.005−1\dfrac{500\times1.005[1.005^8 -1]}{1.005-1}???


No.
Reply 11
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thefatone
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6
Original post by Zacken
No.


i'm not sure i understand what i'm supposed to do, surely i just do what i said above and i'll get the new sum of the money with the new interest?
Reply 12
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Zacken
22
Original post by thefatone
i'm not sure i understand what i'm supposed to do, surely i just do what i said above and i'll get the new sum of the money with the new interest?


Read the question. It says monthly.
Reply 13
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thefatone
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6
Original post by Zacken
Read the question. It says monthly.


i see o.o, another of my many weaknesses
Reply 14
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thefatone
OP
6
Original post by Zacken
Read the question. It says monthly.


right so 500×(1.005)12500\times \left(1.005\right)^{12}

then use this value and plug it back into the formula?
Reply 15
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Zacken
22
Original post by thefatone
right so 500×(1.005)12500\times \left(1.005\right)^{12}

then use this value and plug it back into the formula?


Something like that, yeah. Check if the 500 * should still be there or not.
Reply 16
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thefatone
OP
6
Original post by Zacken
Something like that, yeah. Check if the 500 * should still be there or not.


of course it will the first term is 500x*new ratio*
Reply 17
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Zacken
22
Original post by thefatone
of course it will the first term is 500x*new ratio*


Okay, yeah. Do you get the answer?
Reply 18
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thefatone
OP
6
Original post by Zacken
Okay, yeah. Do you get the answer?


Yup it's same as the mark scheme's
Reply 19
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Zacken
22
Original post by thefatone
Yup it's same as the mark scheme's


Awesome.

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