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Edexcel S3 - Wednesday 25th May AM 2016

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How do you tag people?

https://869d950bf149eefd5cd2652b400160ceb38ca5c7.googledrive.com/host/0B1ZiqBksUHNYVGVDMmVJYzVnRnc/June%202011%20QP%20-%20S3%20Edexcel.pdf

q7d not too sure about this - i got the answer but it was by fluke. Anybody lend me a hand?
Original post by Zacken
On the Edexcel website.


Cheers, didn't see the IAL option. My mistake
Original post by tazza ma razza
How do you tag people?

https://869d950bf149eefd5cd2652b400160ceb38ca5c7.googledrive.com/host/0B1ZiqBksUHNYVGVDMmVJYzVnRnc/June%202011%20QP%20-%20S3%20Edexcel.pdf

q7d not too sure about this - i got the answer but it was by fluke. Anybody lend me a hand?


Is this alright?

P(Xˉμ<1)0.98\displaystyle \mathbb{P}\left ( \left | \bar{X}-\mu \right |< 1 \right )\geqslant 0.98

Unparseable latex formula:

\dispaystyle \bar{X}- \mu\sim \left ( 0,\frac{3^{2}}{n} \right )



P(Z<103n)0.98\displaystyle \Rightarrow \mathbb{P}\left ( \left | Z \right |< \frac{1-0}{\frac{3}{\sqrt{n}}} \right )\geqslant 0.98

13n2.3263 or 13n2.3263\displaystyle -\frac{1}{\frac{3}{\sqrt{n}}} \leqslant -2.3263 \ \text{or} \ \frac{1}{\frac{3}{\sqrt{n}}}\geqslant 2.3263.
Original post by Ayman!
Is this alright?

P(Xˉμ<1)0.98\displaystyle \mathbb{P}\left ( \left | \bar{X}-\mu \right |< 1 \right )\geqslant 0.98

Unparseable latex formula:

\dispaystyle \bar{X}- \mu\sim \left ( 0,\frac{3^{2}}{n} \right )



P(Z<103n)0.98\displaystyle \Rightarrow \mathbb{P}\left ( \left | Z \right |< \frac{1-0}{\frac{3}{\sqrt{n}}} \right )\geqslant 0.98

13n2.3263 or 13n2.3263\displaystyle -\frac{1}{\frac{3}{\sqrt{n}}} \leqslant -2.3263 \ \text{or} \ \frac{1}{\frac{3}{\sqrt{n}}}\geqslant 2.3263.


right - literally had the exact same on my paper, thought it was too good to be true loool

thanks so much
Original post by tazza ma razza
right - literally had the exact same on my paper, thought it was too good to be true loool

thanks so much


Give yourself a break; seems like you're working really hard for this exam. :smile:
Original post by tazza ma razza
How do you tag people?

https://869d950bf149eefd5cd2652b400160ceb38ca5c7.googledrive.com/host/0B1ZiqBksUHNYVGVDMmVJYzVnRnc/June%202011%20QP%20-%20S3%20Edexcel.pdf

q7d not too sure about this - i got the answer but it was by fluke. Anybody lend me a hand?


i'm not sure how to word this, but imagine this as a question about 98% confidence interval. you would get z= 2.3263, and apply the formula to this question, zσ/rootn= 1, put z and σ in, you get n
Another great resource is here: http://www.drfrostmaths.com/page.php?page=21

The Revision PDF has everything you need to know in one document.
Original post by Ayman!
Is this alright?

P(Xˉμ<1)0.98\displaystyle \mathbb{P}\left ( \left | \bar{X}-\mu \right |< 1 \right )\geqslant 0.98

Unparseable latex formula:

\dispaystyle \bar{X}- \mu\sim \left ( 0,\frac{3^{2}}{n} \right )



P(Z<103n)0.98\displaystyle \Rightarrow \mathbb{P}\left ( \left | Z \right |< \frac{1-0}{\frac{3}{\sqrt{n}}} \right )\geqslant 0.98

13n2.3263 or 13n2.3263\displaystyle -\frac{1}{\frac{3}{\sqrt{n}}} \leqslant -2.3263 \ \text{or} \ \frac{1}{\frac{3}{\sqrt{n}}}\geqslant 2.3263.


How did you go from step 3 to step 4?
Original post by JoshC98
How did you go from step 3 to step 4?


Percentage points - draw a normal curve if it isn't clear.
Original post by Euclidean
Does anyone have an idea why 2015 isn't on physicsandmathstutor anymore?

Original post by Zacken
Anymore? I think he was just too lazy/cba to put it up? It's on the Edexcel website anyhow.
Come on, there must be another reason!

Original post by physicsmaths
its weird week before m3 ial june 15 was up then before the exam it was gone....
his website is so big i think he has to be very careful on what he can put up and stuff.
Edexcel is changing their policy and they will keep them locked for 12 months instead of 9 so I was asked to take them down. They still have them on theirs though...
Original post by PhysicsMathsTut
Come on, there must be another reason!

Edexcel is changing their policy and they will keep them locked for 12 months instead of 9 so I was asked to take them down. They still have them on theirs though...


I thought so, weird indeed.
I don't see the point of locking them for another 3 months it won't help anyone.
Original post by physicsmaths
I thought so, weird indeed.
I don't see the point of locking them for another 3 months it won't help anyone.


That's why Arsey's went down as well, I presume.
how do you know when to include the parameters in null and alternative hypotheses for binomial and/or poisson?
Original post by AakashG
how do you know when to include the parameters in null and alternative hypotheses for binomial and/or poisson?


You include them if they're assumed and you don't include them if you calculate it from the observed data.
Reply 815
Original post by SeanFM
:wavey:

As far as I am aware there is nothing special about continuous uniform distributions so I would say that it is most likely a mistake.


Thank you! I have figured it out.
Original post by Zacken
You include them if they're assumed and you don't include them if you calculate it from the observed data.


if it tells you to prove the mean is S in part a, and then in part b is the goodness of fit test, would you still quote p or quote binomial is a suitable model in your hypothesis?

I am never sure if whether or not the mean is assumed when it asks you to prove the mean is a stated value
(edited 7 years ago)
How come we're noy allowed to use the sample mean in 6(a) but we have to use it in 6(b) on June 13R?

@Zacin
Please could someone help with question 2c https://869d950bf149eefd5cd2652b400160ceb38ca5c7.googledrive.com/host/0B1ZiqBksUHNYVGVDMmVJYzVnRnc/June%202014%20(IAL)%20QP%20-%20S3%20Edexcel.pdf how do we know to work out the mean of those 10 values? Thanks :smile:
Original post by economicss
Please could someone help with question 2c https://869d950bf149eefd5cd2652b400160ceb38ca5c7.googledrive.com/host/0B1ZiqBksUHNYVGVDMmVJYzVnRnc/June%202014%20(IAL)%20QP%20-%20S3%20Edexcel.pdf how do we know to work out the mean of those 10 values? Thanks :smile:


We need to work out 2a+3, clearly, so equivalently we need to find a. However, in (b) you just found an unbiased estimator for a based on the mean of the observations. Hopefully you can see how you can use the data they give you from there.

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