AQA Physics AS exam 24th MAY and 9th JUNE 2016 (Thread)

I measured the length across all three antinodes, which resulted in a length of 11.8cm. That is 0.118m wavelength
Frequency = Speed of light in a vacuo (3x10^8)/Wavelength (0.118)
So f = 2.5x10^9

I think so, 12cm

that's the wavelength for 2 waves isnt it?

What material did you choose for the cable for the lift and the cable/rope for bungee jumping???

that's the wavelength for 2 waves isnt it?

Your right if it was in the fundamental mode of vibration but it had 3 antinodes altogether

Wavelengh= length between a pair of nodes times 2.

But since there was already 2 sets of nodes it was just the whole thing = wavelengh

Again please correct me if am wrong (didn't do that well)

I think I got 2.71 or something for the a

Nah, since there were three antinodes so its one complete wave they showed?

Its decceleration so its -2.71

You will probz still get full marks for it if its right god willing.

that's the wavelength for 2 waves isnt it?

Its decceleration so its -2.71

You will probz still get full marks for it if its right god willing.

yeah but the microwave started at the transmitter, not the first node? i'm all ears here

The answer was 2.71 though since it asked for the deceleration
Not -2.71

We have 3 antinodes given to us
One wavelength is the distance from a point on a wave, of given velocity and amplitude, to the adjacent particle on the wave with the same velocity and amplitude

If u look at the diagram the particle motion of the wave at the antinode only reaches the same point by the 3rd antinode

Because of this, the distance across all three antinodes gives 1 wavelength

Acceleration is vector so it should be minus 2.71

Acceleration is vector so it should be minus 2.71