AQA A Level Maths Core 2 - 25th May 2016 [Exam Discussion]

UN-OFFICIAL MARK SCHEME.
Of what I can remember..

1. b) a=2
2. b) x=-0.861
c) reflection in y-axis
3. a) 3x^-1/2 - 1
b) y=6
c) y + 2x = 13
d) k = 5.5
4. b) d = -2, a = 28
c) Sum to 21 - sum to 3. Can't remember exact.
5. b) area = 19.9
c) perimeter = 13.8 (something like that)
6. a) 65.6
b) i) translation (0,5)
ii) stretch in X-direction 1/3 sf
7. b) -1648
8. b) can't remember! Tan(X) = 1 and tan(X) =-5/4
c) lowest = 2, when theta = pi
9. a) c^(m/2 +6n)
b) X = 5/2

Posted from TSR Mobile

I think I got the same for all. 9 was 3^(m/2 -6n)

For 4 U12 was 6
And I think I got -336 for one question

(edited 7 years ago)

Reply 81

cutymoonmoon

4

Original post by Shehryar01

Don't remember the answer but the method i used was to half the area of triangle and then use that to find radius by the area of sector then subbed r into equation of arc length then found perimeter. It was an easy 6 marks. and i did get radius in decimal so the answer was in decimal as well

ohhh thats how you do it, i was completely stumped by that question :frown:

i just wrote area of triangle and half it and i couldnt do the rest...now i feel really stupid :s-smilie:

Reply 82

kroasia

1

Original post by viktorh

I got:

65.6 for the trapezium rule question
6 for U12 near the end
and for the sigma question at the end I got 90???

anyone get any of these

All the same :biggrin:

Reply 83

yelash

10

Original post by BenAtkinson

UN-OFFICIAL MARK SCHEME.
Of what I can remember..

1. b) a=2
2. b) x=-0.861
c) reflection in y-axis
3. a) 3x^-1/2 - 1
b) y=6
c) y + 2x = 13
d) k = 5.5
4. b) d = -2, a = 28
c) Sum to 21 - sum to 3. Can't remember exact.
5. b) area = 19.9
c) perimeter = 13.8 (something like that)
6. a) 65.6
b) i) translation (0,5)
ii) stretch in X-direction 1/3 sf
7. b) -1648
8. b) can't remember! Tan(X) = 1 and tan(X) =-5/4
c) lowest = 2, when theta = pi
9. a) c^(m/2 +6n)
b) X = 5/2
Posted from TSR Mobile

You're answers to 1,2,3,5,6,7,8,9B) seem familiar but not 9 or 4 :/
Think I got a=-28 for 4)b and d=34
I though 9)a) was 3^(n/12m) (possibly with m and n the other way round)

(edited 7 years ago)

Reply 84

Jumay

3

Wow that's extremely frustrating >.> I worked out the arc length aswell just didn't add it. Likely 5 marks for method atleast :L

Reply 85

QuietDragon

1

Original post by Alfie Oliver

Did anyone else get the binomial expansion answer as something like -1000 something it was like -1280 idk tho something around there?

Same here. Something like -1260 or -1280.

Reply 86

jordanwu

13

What does everyone think the grade boundaries will be like? Lower or higher than last year?

Reply 87

tsr1807

2

Original post by Alfie Oliver

Did anyone else get the binomial expansion answer as something like -1000 something it was like -1280 idk tho something around there?

I got this!!

Reply 88

Helicopter06

1

Original post by BenAtkinson

UN-OFFICIAL MARK SCHEME.
Of what I can remember..

1. b) a=2
2. b) x=-0.861
c) reflection in y-axis
3. a) 3x^-1/2 - 1
b) y=6
c) y + 2x = 13
d) k = 5.5
4. b) d = -2, a = 28
c) Sum to 21 - sum to 3. Can't remember exact.
5. b) area = 19.9
c) perimeter = 13.8 (something like that)
6. a) 65.6
b) i) translation (0,5)
ii) stretch in X-direction 1/3 sf
7. b) -1648
8. b) can't remember! Tan(X) = 1 and tan(X) =-5/4
c) lowest = 2, when theta = pi
9. a) c^(m/2 +6n)
b) X = 5/2

Posted from TSR Mobile

for 6bii i got stretch in y-direction scale factor 3

Reply 89

viktorh

1

Original post by jordanwu

What does everyone think the grade boundaries will be like? Lower or higher than last year?

For a c2 test i found that pretty easy so I'd assume they'll go up

Reply 90

Shehryar01

Original post by yelash

You're answers to 1,2,3,5,6,7,8,9B) seem familiar but not 9 or 4 :/
Think I got a=-28 for 4)b and d=34

I got same for 4 as in unofficial MS and for 9 there was a number instead of c which i think was 3

Reply 91

Shehryar01

Original post by jordanwu

What does everyone think the grade boundaries will be like? Lower or higher than last year?

i think it may be just a bit higher than last years

Reply 92

Poppy1098

1

Original post by MotorboatMyGoat

I think I got the same for all. 9 was 3^(m/2 -6n)

For 4 U12 was 6
And I think I got -336 for one question

I think it should be m/2 -6n as when you divide you take away powers?

Reply 93

M.N1997

For the 3(x^3 + 1)^1/2 translation, I took the 3 into the square root and times it all by factor nine, this gave me stretch in X direction sf 1/9??

Reply 94

Ben4444

6

Original post by BenAtkinson

UN-OFFICIAL MARK SCHEME.
Of what I can remember..

1. b) a=2
2. b) x=-0.861
c) reflection in y-axis
3. a) 3x^-1/2 - 1
b) y=6
c) y + 2x = 13
d) k = 5.5
4. b) d = -2, a = 28
c) Sum to 21 - sum to 3. Can't remember exact.
5. b) area = 19.9
c) perimeter = 13.8 (something like that)
6. a) 65.6
b) i) translation (0,5)
ii) stretch in X-direction 1/3 sf
7. b) -1648
8. b) can't remember! Tan(X) = 1 and tan(X) =-5/4
c) lowest = 2, when theta = pi
9. a) c^(m/2 +6n)
b) X = 5/2

Posted from TSR Mobile

Why did you get tan(X)=1 and tan(X)=-5/4 for 8b? I only got tan(X)=-5/4 and got 2 solutions from it

Reply 95

yelash

10

Original post by Poppy1098

I think it should be m/2 -6n as when you divide you take away powers?

Dam I think I divided the powers :/// stupid me. How many marks was that?

Reply 96

TIF141

11

Original post by jordanwu

Oh crap I got c^m/2 -6n :/

I think it was -6n, because it's a division, right??

Reply 97

kiiten

18

Original post by gardenGnostic

I got like ~3.41 for the arc length for the triangle and something like ~5.86 for r. I think you had to say that 1/2 r^2 x = 19.9(area of triangle)-1/2 r^2 x, therefore r^2 x = 19.9. You already know x, so substitute it in and get r^2 to be ~34 and r = 5.86 ish. Final perimeter should be about 13.7 or 13.8 depending on how you've rounded in the question.

Of course, I could be completely wrong :smile:

No, i got that too :smile:

Reply 98

AmazingAl

1

Original post by Ben4444

Why did you get tan(X)=1 and tan(X)=-5/4 for 8b? I only got tan(X)=-5/4 and got 2 solutions from it

Because one of the brackets that the question gave was (1-tanx), therefore tanx =1 is a thing

Reply 99

Shehryar01

Original post by Ben4444

Why did you get tan(X)=1 and tan(X)=-5/4 for 8b? I only got tan(X)=-5/4 and got 2 solutions from it

the question gave us a factorised quadratic so in first (1-tanx) it was one solution and the other one you had to sub in tanx=-5/4 from previous question and equal it to zero therefore 2 solutions from each so 4 in total

AQA A Level Maths Core 2 - 25th May 2016 [Exam Discussion]

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